Answer:
The equation in point-slope is 
Step-by-step explanation:
We need to write the point-slope form of the equation of the line passing through the point (6,-5) and perpendicular to the line 
The general form of point-slope is; 
where m is slope and
is the point
We need to calculate slope.
We are given equation of line
that is perpendicular to the required line.
The equation is given in slope-intercept form
where m is slope.
Comparing both equations we get m= -1/3
But we know that when lines are perpendicular their slopes are opposite reciprocal of each other i.e 
<em>So, </em><em>slope of required line is m = 3 </em><em>(opposite reciprocal of -1/3)</em>
Now, the equation in point-slope form having slope m=3 and point (6,-5) is

So, The equation in point-slope is 
2x = 8 - 5y
x = 8/2 - 5y/2
x = 4 - 2.5 y
or
x = 4 - 5/2 y
Answer:
−2x2+16x−8
Step-by-step explanation:
Answer:

Step-by-step explanation:
Using FOIL (First, outer, inner, last)
First, we multiply 3x and x to get
(First)
We then multiply 3x and 1 to get
(outer)
Then 4 and x to get
(Inner)
Then multiply 1 and 4 to get
(last)
Since the quadratics are all positive, we add all the terms together to get:
. Since 3x and 4x are like terms, we add them together and simplify to get:

And since we can't simplify any further, that's our answer!
Hope this helps :D