Using the Central Limit Theorem, it is found that the correct option is:
- B) The random sample of 15 meerkats should be close to 5.2 years-old.
The <em>Central Limit Theorem</em> states that taking a sample of size n for a population of mean , the sample means are going to be close to .
- The larger the value of n, the closer the sample mean should be to
In the context of this problem, the sample mean should be close to 5.2 years old, and the correct option is B.
For more on the Central Limit Theorem, you can check brainly.com/question/25581475
Answer: F=140
Step-by-step explanation:
720=(x-60)+(x-40)+(x-20)+130+120+110
720-130-120-110=3x-120
360=3x-120
360+120=3x
480=3x
480/3=x
160=x
F=160-20
Next problem
102+31+x=180
133+x=180
x=180-133
x=47
If the 10 videotapes are distinct (different) and the order of selection is immaterial, then there are
C(10,3)=10!/(3!(10-3)!)=10!/(3!7!)=10*9*8/(1*2*3)=120
ways to select three videotapes out of 10.
9514 1404 393
Answer:
R32.15
Step-by-step explanation:
Let x and y represent the original price of a loaf of bread and a liter of drink, respectively. The two relations given by the problem statement are ...
10x +12y = 138.90
10(1.2x) +12(1.1y) = 159.54
Multiplying the first equation by 1.2 and subtracting the second gives ...
1.2(10x +12y) -(10(1.2x) +12(1.1y)) = 1.2(138.90) -(159.54)
1.2y = 7.14 . . . . collect terms
y = 5.95 . . . . . divide by 1.2
The value of x can be found from the first equation.
10x + 12(5.95) = 138.90
10x = 67.50 . . . . . . . . . . . subtract 71.40
x = 6.75 . . . . divide by 10
Then the value of 3x+2y is ...
3(6.75) +2(5.95) = 32.15
The original price of 3 loaves and 2 liters is R31.15.