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3 years ago

30 POINTS

Mathematics

1 answer:

MaRussiya [10]3 years ago

8 0

Using the Central Limit Theorem, it is found that the correct option is:

B) The random sample of 15 meerkats should be close to 5.2 years-old.

The <em>Central Limit Theorem</em> states that taking a sample of size n for a population of mean $\mu$ , the sample means are going to be close to $\mu$ .

The larger the value of n, the closer the sample mean should be to $\mu$

In the context of this problem, the sample mean should be close to 5.2 years old, and the correct option is B.

For more on the Central Limit Theorem, you can check brainly.com/question/25581475

You might be interested in

A students cost for last semester at her community college was $2500. She spent $475 of that on books.what percent of last semes

max2010maxim [7]

It is 19%!! :) an explanation is:
We assume, that the number 2500 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 100% equals 2500, so we can write it down as 100%=2500.
4. We know, that x% equals 475 of the output value, so we can write it down as x%=475.
5. Now we have two simple equations:
1) 100%=2500
2) x%=475
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
100%/x%=2500/475
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for 475 is what percent of 2500

100%/x%=2500/475
(100/x)*x=(2500/475)*x - we multiply both sides of the equation by x
100=5.2631578947368*x - we divide both sides of the equation by (5.2631578947368) to get x
100/5.2631578947368=x
19=x
x=19

now we have:
475 is 19% of 2500

7 0

4 years ago

for the first 18 days of the month, buffet dinner generate $11,800 in sales. The buffet sale target for the month is $18,650. Gi

sesenic [268]

Your Daily Sale Goal should be $611.61 to achieve the $18.65k monthly goal

8 0

3 years ago

Teo makes a necklace of x wooden beads at $0.50 each and 6 glass beads at $1.25 each. The average cost of the beads in the neckl

Ainat [17]

Answer:

0.50x + 7.50 = 0.75(x+6)

Hope this helps :)

4 0

4 years ago

Aisha went shopping for a new video game because of a sale. The store was offering a 5% discount. If the price on the tag was $2

Anastasy [175]

Answer:

$25.65

Step-by-step explanation:

Since we are applying a discount to a price tag, we will be <u>decreasing</u> the amount of that price tag.

In this case, we will be taking 5% off of $27. This means that our new price tag will be 95% of what it originally was. To find the answer, we must first change 95% into a decimal.

95% -> $\frac{95}{100}$ -> 0.95

Next, we multiple $27 by 0.95 as shown below:

$27(0.95)$

Our answer will be:

$25.65

8 0

3 years ago

I tell you these facts about a mystery number, $c$: $\bullet$ $1.5 < c < 2$ $\bullet$ $c$ can be written as a fraction wit

makkiz [27]

Answer:

Possible answer: $\displaystyle c = \frac{16}{10} = \frac{8}{5} = 1.6$ .

Step-by-step explanation:

Rewrite the bounds of $c$ as fractions:

The simplest fraction for $1.5$ is $\displaystyle \frac{3}{2}$ . Write the upper bound $2$ as a fraction with the same denominator:

$\displaystyle 2 = 2 \times 1 = 2 \times \frac{2}{2} = \frac{4}{2}$ .

Hence the range for $c$ would be:

$\displaystyle \frac{3}{2} < c < \frac{4}{2}$ .

If the denominator of $c$ is also $2$ , then the range for its numerator (call it $p$ ) would be $3 < p < 4$ . Apparently, no whole number could fit into this interval. The reason is that the interval is open, and the difference between the bounds is less than $2$ .

To solve this problem, consider scaling up the denominator. To make sure that the numerator of the bounds are still whole numbers, multiply both the numerator and the denominator by a whole number (for example, 2.)

$\displaystyle \frac{3}{2} = \frac{2 \times 3}{2 \times 2} = \frac{6}{4}$ .

$\displaystyle \frac{4}{2} = \frac{2\times 4}{2 \times 2} = \frac{8}{4}$ .

At this point, the difference between the numerators is now $2$ . That allows a number ( $7$ in this case) to fit between the bounds. However, $\displaystyle \frac{1}{c} = \frac{4}{7}$ can't be written as finite decimals.

Try multiplying the numerator and the denominator by a different number.

$\displaystyle \frac{3}{2} = \frac{3 \times 3}{3 \times 2} = \frac{9}{6}$ .

$\displaystyle \frac{4}{2} = \frac{3\times 4}{3 \times 2} = \frac{12}{6}$ .

$\displaystyle \frac{3}{2} = \frac{4 \times 3}{4 \times 2} = \frac{12}{8}$ .

$\displaystyle \frac{4}{2} = \frac{4\times 4}{4 \times 2} = \frac{16}{8}$ .

$\displaystyle \frac{3}{2} = \frac{5 \times 3}{5 \times 2} = \frac{15}{10}$ .

$\displaystyle \frac{4}{2} = \frac{5\times 4}{5 \times 2} = \frac{20}{10}$ .

It is important to note that some expressions for $c$ can be simplified. For example, $\displaystyle \frac{16}{10} = \frac{2 \times 8}{2 \times 5} = \frac{8}{5}$ because of the common factor $2$ .

Apparently $\displaystyle c = \frac{16}{10} = \frac{8}{5}$ works. $c = 1.6$ while $\displaystyle \frac{1}{c} = \frac{5}{8} = 0.625$ .

8 0

4 years ago

Read 2 more answers