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2 years ago

Evaluate the expression, when p= 6 P^2 - 18?

Mathematics

1 answer:

garri49 [273]2 years ago

8 0

Answer:

Step-by-step explanation:

P^2 - 18

Let p=6

6^2 -18

36 - 18

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Consider these three numbers expressed in scientific notation 2.4 x10^4 , 6.3 x10^5 , and 9.6 x10^7

____ [38]

I considered them, but if you wanted them evaluated, here you go
24,000
630,000
96,000,000

8 0

2 years ago

The half-life of cesium-137 is 30 years. Suppose we have a

VMariaS [17]

(a) If $y(t)$ is the mass (in mg) remaining after $t$ years, then $y(t) = y(0) e^{kt}=100e^{kt}.$

$y(30) = 100 e^{30k} = \frac{1}{2}(100) \implies e^{30k} = \frac{1}{2} \implies k = -(\ln 2) /30 \implies \\ \\
y(t) = 100e^{-(\ln 2)t/30} = 100 \cdot 2^{-t/30}$

(b) $y(100) = 100 \cdot 2^{-100/30} \approx \text{9.92 mg}$

(c)
$100 e^{- (\ln 2)t/30} = 1\ \implies\ -(\ln 2) t / 30 = \ln \frac{1}{100}\ \implies\ \\ \\
t = -30 \frac{\ln 0.01}{\ln 2} \approx \text{199.3 years}$

3 0

2 years ago

Write a program that accepts a whole number as Input multiplies that number by 12 the outputs the product

frez [133]

Answer:

Step-by-step explanation:

programs can be written in multiply languages. for this solution I'll be writing in C++.

#include<iostream> // this is called the preprocessor definition

using namespace std;

int main() //the main function

{

int num, product; //declaration of the variables

cout << "enter the whole number";

cin >> num;

product = num * 12;

cout << product; // displaying the final results

return 0;

}

7 0

3 years ago

Solve 4 over x plus 2 equals 2 over x for x and determine if the solution is extraneous or not.

shtirl [24]

X = 2, not extraneous.

5 0

2 years ago

Read 2 more answers

Help me plsss the photo is down fast

kiruha [24]

Answer:

<h2>Option B:</h2><h2> $\frac{1}{5}$ </h2>

Step-by-step explanation:

Given,

Number of numbers of each side of the cube

= 4, 5, 6, 7, 8 and 9

= 6 numbers

Number of sides of cube having the number 5

= 1

Therefore, 

Probability of getting a side of the cube of no. 5 is

$= \frac{no. \: of \: favourable \: outcomes}{total \: no. \: of \: possible \: outcomes}$

$= \frac{1}{6} (ans) \: (option \: B)$

8 0

2 years ago