In the figure below. AB is a diameter of circle P.

Your grocery bill before taxes was $265.24. You have to pay 7.3% sales tax. How much is your total grocery bill?

tamaranim1 [39]

Answer:

$284.60

Step-by-step explanation:

7.3% of $265.24 = 19.36252,

So the tax is $19.36.

19.36 + 265.24 = 284.60

So the total grocery bill is $284.60.

6 0

3 years ago

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What combination of variables could you analyze using correlation?

Anon25 [30]

Answer:

YOu have to add them i think

Step-by-step explanation:

First add the 3-4 and then finish it

3 0

3 years ago

In physics class, Carrie learns that a force, G, is equal to the mass of an object, m, times its acceleration, a. She writes the

wlad13 [49]

Your problem statement is missing the formula Carrie came up with. It should be The one she started with, divided by m.

... G/m = a

For the values given, the acceleration is

... (7.92 N)/(3.6 kg) = 2.2 m/s²

_____

The unit of newtons is abbreviated N.

1 N = 1 kg·m/s² so dividing by kilograms leaves units of m/s², which are the units of acceleration.

Very likely, your question is not concerned with the units, just the number: 2.2. It's a straight division problem, easily handled by hand, by calculator, or in your head (after you realize 7.92 = 7.2×1.1 = 2×3.6×1.1).

6 0

3 years ago

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What is the derivative of 1/square root 4x.

Bumek [7]

Answer:

$\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4x^\bigg{\frac{3}{2}}}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Exponential Properties

Exponential Property [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Property [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

Identify.

$\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg]$

Step 2: Differentiate

Simplify: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \bigg( \frac{1}{2\sqrt{x}} \bigg)'$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{1}{\sqrt{x}} \bigg)'$
Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{1}{x^\Big{\frac{1}{2}}} \bigg)'$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( x^\bigg{\frac{-1}{2}} \bigg)'$
Derivative Rule [Basic Power Rule]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{-1}{2} x^\bigg{\frac{-3}{2}} \bigg)$
Simplify: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4} x^\bigg{\frac{-3}{2}}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4x^\bigg{\frac{3}{2}}}$