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3 years ago

HELPPPPPPPPP+ EXPAINNNNNNNN

Mathematics

1 answer:

Nimfa-mama [501]3 years ago

5 0

C. 16-x^2=/=0 so x=/=+-2 Horizontal Asymptope can be found by the ratio of the highest power of x in denominator and highest power of x in numerator which is 1.

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Rewrite the square-root expression as an imaginary number: sqrt of -64 is it 8i?

IceJOKER [234]

The answer is 8i.

i = √(-1)

√(-64) = √((-1) * 64)
= √(-1) * √64
= i * √8²
= i * 8
= 8i

6 0

3 years ago

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What is 0.572 divide by 4

Daniel [21]

Answer:

0.143

Step-by-step explanation:

Please mark me as Brainliest if you are satisfied with the answer.

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3 years ago

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Rewrite the subtraction as addition 3- (-10)

Bumek [7]

Rewrite the subtraction as addition 3- (-10)

= 3 + 10

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3 years ago

What is the value of i 97 – i? –i 0 –2i i Superscript 96

Valentin [98]

The question is not clearly readable, but I'm assuming the expression which makes more sense, so you can have a clue

Answer:

$i^{97}-i=0$

Step-by-step explanation:

Powers of The Imaginary Unit

The imaginary unit i is defined as

$i=\sqrt{-1}$

The first powers of i are

$i^0=1$

$i^1=i$

$i^2=(\sqrt{-1})^2=-1$

$i^3=i.i^2=-i$

$i^4=i^2.i^2=1$

And so on the cycle repeats every four numbers. To find the value of $i^{96}$ we can find the remainder of 96/4=0. So $i^{96}=i^0=1$

The given expression is

$i^{97}-i$

Factoring

$i(i^{96}-1)$

Since $i^{96}=1$

$=i(1-1)=0$

The required value is 0

6 0

3 years ago

Read 2 more answers

Select the correct answer.

ad-work [718]

Answer:

A' (-1, 2)

Step-by-step explanation:

(x, y) -> (-y, x)

A' (-1, 2)

B' (1, -2)

C' (2, -2)

D' (0, -2)

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3 years ago