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hammer [34]
2 years ago
7

Please help me out!!!!!

Mathematics
1 answer:
valentina_108 [34]2 years ago
5 0

Answer:

Option (5)

Step-by-step explanation:

f(x) is a function with the degree of 3, having zeros as x = 2, 2t, -2t

And f(1) = -15

Option (1)

f(x) = 2x³- 2x² + 2x - 30

f(1) = 2(1)³ - 2(1)² + 2(1) - 30

    = 2 - 2 + 2 - 30

    = -28 ≠ -15

Therefore, Option (1) is not the answer.

Option (2)

f(x) = 2x³ + 2x² + 2x - 30

f(1) = 2(1)³ + 2(1)² + 2(1) - 30

    = 2 + 2 + 2 - 30

    = 6 - 30

    = -24 ≠ -15

Therefore, Option (2) is not the answer.

Option (3)

f(x) = 3x³ - 6x² + 12x - 12

f(1) = 3(1)³ - 6(1)² + 12(1) - 12

    = 3 - 6

    = -3 ≠ -15

Therefore, Option (3) is not the answer.

Option(4)

f(x) = 48x³- 9x² + 12x - 24

f(1) = 48(1)³ - 9(1)² + 12(1) - 24

    = 48 - 9 + 12 - 24

    = 27 ≠ -15

Therefore, Option (4) is not the answer.

Option (5)

f(x) = 3x³- 6x² + 12x - 24

f(1) = 3(1)³- 6(1)² + 12(1) - 24

    = 3 - 6 + 12 - 24

    = -15

Therefore, Option (5) is the correct option.

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Step-by-step explanation:

For each drill, there are only two possible outcomes. Either it is a strike, or it is not. Each drill is independent of other drills. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

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In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

20% chance of striking oil.

This means that p = 0.2

What is that probability that the third strike comes on the seventh well drilled

2 stikers during the first 6 drills(P(X = 2) when n = 6)[/tex]

Strike during the 7th drill, with 0.2 probability. So

P = 0.2P(X = 2)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

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Then

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4.92% probability that the third strike comes on the seventh well drilled

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