Answer:
3rd then 1st then 2nd then 4th
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3(2c+d)-4(c-d)+d^2
c=1 , d=3
Use the substitution method
3(2*1+3)-4(1-3)+3^2
Multiply the brackets
3(2+3)-4+12+9
6+9-4+12+9
15-4+12+9
11+21
=32
Answer: 32
Answer:
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Step-by-step explanation: