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Vera_Pavlovna [14]

2 years ago

12

This one please. Thank you!!

2 answers:

lys-0071 [83]2 years ago

5 0

I’m believe it’s the 3rd one but i’m not sure

Ilya [14]2 years ago

5 0

Answer:

The answer highlighted in yellow in your picture looks like the correct answer to me!

Step-by-step explanation:

hope this is helpful!

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What is (2x^2+6x-3) added to (2x^3-3x+2)?

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2x² + 6x - 3 + 2x³ - 3x + 2

Combine like terms

2x³ + 2x² + 6x - 3x - 3 + 2

Final answer:
2x³ + 2x² + 3x - 1

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Subtract 2b by both sides which gets -b+4=-5 then subtract 4 by both sides so you get -b=-9 and divide -1 by both sides so that b=9

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The graph below shows the average daily temperatures on January 1 from 1900 to 1934 for city A.

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Step-by-step explanation:

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3 years ago

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A company is bidding on two projects, A and B. The probability that the company wins project A is 0.40 and the probability that

kondaur [170]

Answer:

Probability that the company wins project A or project B is 0.50.

Step-by-step explanation:

We are given that a company is bidding on two projects, A and B. The probability that the company wins project A is 0.40 and the probability that the company wins project B is 0.25.

Also, Winning project A and winning project B are independent events.

Let the Probability of winning project A = P(A) = 0.40

Probability of winning project B = P(B) = 0.25

<u>Now, as we know that ;</u>

Probability that the company wins project A or project B = $P(A \bigcup B)$

$P(A \bigcup B) = P(A) + P(B) - P(A \bigcap B)$

So, we have to find the value of Probability of winning project A and B, i.e;

$P(A \bigcap B)$

<em>Since, we are given that Winning project A and winning project B are independent events which means when this condition is given then;</em>

$P(A \bigcap B) = P(A) \times P(B)$

= 0.40 $\times$ 0.25 = 0.10

Now, Probability that the company wins project A or project B is given by;

$P(A \bigcup B) = P(A) + P(B) - P(A \bigcap B)$

= 0.40 + 0.25 - 0.10

= 0.65 - 0.10 = 0.55

Hence, probability that the company wins project A or project B is 0.50.

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