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Katarina [22]
3 years ago
8

How many bases are there in the triangular pyramid shown below?

Mathematics
2 answers:
sukhopar [10]3 years ago
5 0

Answer:

1

Step-by-step explanation:

muminat3 years ago
5 0

Answer:

1

Step-by-step explanation:

In a pyramid, there is only one base that touches the ground.

However, in a prism, there are two bases, two of the same ends.

The front of the name of the shape also hints:

If it's an octagonal prism, there are two octagon bases.

If it's a hexagonal pyramid, there is one hexagon base.

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(-7,-3) and (-12,5)<br> What passes through the slope intercept
harina [27]

Find the slope of the line through (x1,y1) = (-7,-3) and (x2,y2) = (-12,5)

m = (y2 - y1)/(x2 - x1)

m = (5 - (-3))/(-12 - (-7))

m = (5 + 3)/(-12 + 7)

m = (8)/(-5)

m = -8/5

-------------

Plug m = -8/5 and (x1,y1) = (-7,-3) into the point slope formula. Solve for y.

y - y1 = m(x - x1)

y - (-3) = (-8/5)(x - (-7))

y + 3 = (-8/5)(x + 7)

y + 3 = (-8/5)x + (-8/5)(7) .... distribute

y + 3 = (-8/5)*x - 56/5 .... multiply

y + 3 - 3 = (-8/5)*x - 56/5 - 3 ... subtract 3 from both sides

y = (-8/5)*x - 56/5 - 15/5 ... rewrite "3" as "15/5"

y = (-8/5)*x - 71/5 .... combine like terms

This equation is in slope-intercept form y = mx+b with m = -8/5 = -1.6 as the slope and b = -71/5 = -14.2 as the y intercept.

-------------

If you want the equation in standard form (Ax+By = C), then you could follow these steps shown below

y = (-8/5)*x - 71/5

5y = 5((-8/5)*x - 71/5) ... multiply both sides by 5

5y = -8x - 71

5y+8x = -8x - 71+8x ... add 8x to both sides

8x+5y = -71

This is in the form Ax+By = C with A = 8, B = 5, C = -71.

8 0
3 years ago
Find the lowest common denominator of and . A. x3y4 B. x2y3 C. xy4 D. x4y5
Blizzard [7]
Lowest Common Denominator refers to lowes t common multiple. These expressions have two terms 'x' and 'y' and we want to choose the expression that has the highest power such that the other expressions can be multiplied into the common denominator.

For the 'x' term, the highest power is x⁴ and for the 'y' term, the highest power is y⁵

Common denominator of A, B, C, and D: x⁴y⁵




5 0
4 years ago
Suppose you want to buy a new car and are trying to choose between two models: Model A: costs $16,500 and its gas mileage is 25
laila [671]

Answer:

1. CA=16,500+5,050x

2. CB=24,500+3,450x

3. CA(x=5)=CB(x=5)=41,750

If keeped 4 years, Model A is more economical.

4. 5 years

5. From month 49 to 61.

6. The cost of ownership of Model A increases more than Model B, as it is less gas efficient. The break-even point for x is reduced from x=5 to x=2.35.

7. The fixed cost are reduced by a 40%, so the variable cost, the ones that depend on time of ownership, are increased in importance.

Step-by-step explanation:

We can express the cost of ownership as the sum of the purchase cost, gas cost and insurance cost.

1. For model A we have:

\text{Cost of ownership}=\text{Purchase cost}+\text{Gas cost}+\text{Insurance cost}\\\\\text{Cost of ownership}=\$16,500+3 \dfrac{\$}{gal}\cdot\dfrac{1\,gal}{25\,miles}\cdot \dfrac{40,000\,miles}{year}\cdot x+\$250\cdot x\\\\\\\text{Cost of ownership}=\$16,500+\$4,800x+\$250x\\\\\\\text{Cost of ownership}=$16,500+\$5,050x

2. For model B we have:

\text{Cost of ownership}=\text{Purchase cost}+\text{Gas cost}+\text{Insurance cost}\\\\\text{Cost of ownership}=\$24,500+3 \dfrac{\$}{gal}\cdot\dfrac{1\,gal}{40\,miles}\cdot \dfrac{40,000\,miles}{year}\cdot x+\$450\cdot x\\\\\\\text{Cost of ownership}=\$24,500+\$3,000x+\$450x\\\\\\\text{Cost of ownership}=$24,500+\$3,450x

3. If x=5, the costs for each car are:

\text{CoOwn A}=16,500+5,050\cdot(5)=16,500+25,250=41,750\\\\\\\text{CoOwn B}=24,500+3,450\cdot(5)=24,500+17,250=41,750

5 years is the break-even point for the cost of ownership between these two cars.

If you plan to keep the car for 4 years, the costs are:

\text{CoOwn A}=16,500+5,050\cdot(4)=16,500+20,200=36,700\\\\\\\text{CoOwn B}=24,500+3,450\cdot(4)=24,500+13,800=38,300

For a 4 year period ownership, the model A is more economical ($36,700).

4. This happens for 1 year, the fifth year, in which the two models have the same cost of ownership.

5. At the 5th year, the cost for both models are the same.

Then, this corresponds to the months 4*12+1=48+1=49 and 5*12+1=61.

6. If the cost of gas doubles, the cost of ownership would rise for both model, but more for the Model A, which is less gas efficient and hence has a higher gas cost.

Model A

\text{Cost of ownership}=\text{Purchase cost}+\text{Gas cost}+\text{Insurance cost}\\\\\text{Cost of ownership}=\$16,500+6 \dfrac{\$}{gal}\cdot\dfrac{1\,gal}{25\,miles}\cdot \dfrac{40,000\,miles}{year}\cdot x+\$250\cdot x\\\\\\\text{Cost of ownership}=\$16,500+\$9,600x+\$250x\\\\\\\text{Cost of ownership}=$16,500+\$9,850x

Model B

\text{Cost of ownership}=\text{Purchase cost}+\text{Gas cost}+\text{Insurance cost}\\\\\text{Cost of ownership}=\$24,500+6 \dfrac{\$}{gal}\cdot\dfrac{1\,gal}{40\,miles}\cdot \dfrac{40,000\,miles}{year}\cdot x+\$450\cdot x\\\\\\\text{Cost of ownership}=\$24,500+\$6,000x+\$450x\\\\\\\text{Cost of ownership}=$24,500+\$6,450x

The breakeven point goes from x=5 (for $3 per gallon) to x=2.35 (for $6 per gallon).

16,500+9,850x=24,500+6,450x\\\\(9,850-6,450)x=24,500-16,500\\\\x=8,000/3400=2.35

7. If we can sell any car for 40% of its value at any time, the cost of ownership becames:

Model A:

\text{Cost of ownership}=16,500+5,050x-0.4\cdot16,500\\\\\text{Cost of ownership}=9,900+5,050x

Model B

\text{Cost of ownership}=24,500+3,450x-0.4\cdot24,500\\\\\text{Cost of ownership}=14,700+3,450x

The fixed costs are lowered by 40%, so the variable costs (the ones that depend on time) became more important.

4 0
4 years ago
a baby weighed8 pounds when she was first bornshe weighes 15 pounds after her doctors check up what was her percent increase fro
zubka84 [21]
The baby 7 lbs increased
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3 years ago
Solve : 11 (9-v)=0 a) -9 b) 9 c) 99 d)-99
garri49 [273]
B. V=9 Multiply it out, then subtract 99 from both sides, then divide by 11
7 0
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