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2 years ago

Help help help help help help plz plz plz plz

Mathematics

1 answer:

olga2289 [7]2 years ago

8 0

21.

This is because on a normal draw, he should expect a result chance of 3/10. Changing it to fit the 70 times, you would change the denominator to 70. 10 to 70 is times 7, so three would be multiplied by seven as well.

Hope this helps!

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Polygon ABCD is a parallelogram, and m of abc =127°. The length of bc is 19 units, and an is 5 units. What is the perimeter of t

hjlf

The perimeter of a parallelgram is the sum of the lengths of its four sides.

Parallelogram ABCD has sides AB, BC, CD, and AB.

Sides AB and CD are parallel and of equal length = 19 units.

Sides BC and CD are parallel and of equal length. Assuming thi is the length of 5 units given in the statement, the perimeter of the parallelogram ABCD is: 19 units + 19 units + 5 units + 5 units = 48 units.

Please, inform if the length of 5 units corresponds to other distance, but even in that case, with this explanation you should be able to calculate the perimeter of this and other parallelograms.

Answer: 48 untis.

6 0

3 years ago

If 6 x 7 = 26 +0, find the number that belongs in the box. 211

Blababa [14]

Answer: 185 sorry if wrong

3 0

2 years ago

If w= the weight of a trout, which algebraic expression represents the phrase

RoseWind [281]

Answer:

it would be w7

Step-by-step explanation:

because to get w you mulitply w with 7

so all that you need to do is put the 7 next to the w

because mathematicians are known to be lazzy so they do not put the multiplication sign, instead the put it next to each other meaning that it is mulitplied

simple awnser for the simple question

6 0

2 years ago

a map has a scale of 2in: 6mi. if a two twons on a map is 10 in apart then how far apart are the real twons

Brilliant_brown [7]

Answer: 30 miles

Work Shown:

2 in : 6 mi

5*2 in : 5*6 mi

10 in : 30 mi

7 0

2 years ago

assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra

Tanzania [10]

Answer:

The probability that at least 4 of them use their smartphones is 0.1773.

Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = Number of adults who use their smartphones

The above situation can be represented through the binomial distribution;

$P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......$

where, n = number of trials (samples) taken = 15 adult smartphones

r = number of success = at least 4

p = probability of success which in our question is the % of adults

who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X $\geq$ 4)

P(X $\geq$ 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= $1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}$

= $1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})$

= 0.1773

3 0

3 years ago