A dealer gained a 10% profit by selling an article for Birr 330.00. what was original price of the article

Dominic, Ralf and Peter have just eaten a HUGE Christmas meal. Dominic now weighs half as much as Ralf, and Peter weighs three t

Strike441 [17]

Dominic weighs 120.

I started laughing as soon as I saw this question...

It honestly made my day:)

4 0

3 years ago

In a certain card game you draw one card off a standard deck of 52 cards. If you draw a spade you get paid $12, if you draw a re

Mariulka [41]

Step-by-step explanation:

In a standard deck of 52 cards, there are 2 red aces, 2 red Queens, and 13 spades. That leaves 35 cards for everything else.

For the game to be fair, the cost must equal the expected value. The expected value is the sum of each outcome times its probability.

C = (12) (13/52) + (20) (2/52) + (38) (2/52) + (0) (35/52)

C = 68/13

C ≈ 5.2308

4 0

3 years ago

Marvin lives in Stormwind City and works as an engineer in the city of Ironforge. In the morning, he has 333 transportation opti

sukhopar [10]

The event "Atleast once" is the complement of event "None".

So, the probability that Marvin teleports atleast once per day will the compliment of probability that he does not teleports during the day. Therefore, first we need to find the probability that Marvin does not teleports during the day.

At Morning, the probability that Marvin does not teleport = 2/3

Likewise, the probability tha Marvin does not teleport during evening is also 2/3.

Since the two events are independent i.e. his choice during morning is not affecting his choice during the evening, the probability that he does not teleports during the day will be the product of both individual probabilities.

So, the probability that Marvin does not teleport during the day = $\frac{2}{3}*\frac{2}{3}=\frac{4}{9}$

Probability that Marvin teleports atleast once during the day = 1 - Probability that Marvin does not teleport during the day.

Probability that Marvin teleports atleast once during the day = $1-\frac{4}{9}=\frac{5}{9}$

5 0

3 years ago

Write an equation in Slope-Intercept Form using the table below.

Veseljchak [2.6K]

Answer:

y = x + 46

Step-by-step explanation:

When writing an equation of a line, keep in mind that you always need the following information in order to determine the linear equation in slope-intercept form, y = mx + b:

1. 2 sets of ordered pairs (x, y)

2. Slope (m)

3. Y-intercept (b)

First, choose two pairs of coordinates to use for solving the slope of the line:

Let (x1, y1) = (0, 46)

(x2, y2) = (1, 47)

User the following formula for slope

$m = \frac{y2 - y1}{x2 - x1}$

Plug in the values of the coordinates into the formula: $m = \frac{y2 - y1}{x2 - x1} = \frac{47 - 46}{1 - 0} = \frac{1}{1} = 1$

Therefore, the slope (m) = 1.

Next, we need the y-intercept, (b). The y-intercept is the y-coordinate of the point where the graph of the linear equation crosses the y-axis. The y-intercept is also the value of y when x = 0. The y-coordinate of the point (0, 46) is the y-intercept. Therefore, b = 46.

Given the slope, m = 1, and y-intercept, b = 46, the linear equation in slope-intercept form is:

y = x + 46

Please mark my answers as the Brainliest if you find my explanations helpful :)

8 0

3 years ago

A study investigated about 3000 meals ordered from Chipotle restaurants using the online site Grubhub. Researchers calculated th

Allisa [31]

Answer:

21.186%

Step-by-step explanation:

z = (x-μ)/σ,

where

x is the raw score = 2400mg

μ is the population mean = 2000mg

σ is the population standard deviation = 500mg

z = 2400 - 2000/500

z = 0.8

Probability value from Z-Table:

P(x<2400) = 0.78814

P(x>2400) = 1 - P(x<2400) = 0.21186

Converting to percentage:

0.21186 × 100

= 21.186%

Therefore, the percent of the meals

ordered that exceeded the recommended daily allowance of 2400 mg of sodium is 21.186%

7 0

3 years ago

A dealer gained a 10% profit by selling an article for Birr 330.00. what was original price of the article​

A dealer gained a 10% profit by selling an article for Birr 330.00. what was original price of the article