Answer:
BC =21.03540021
Step-by-step explanation:
We know the measure of angle B since the sum of the angles of a triangle add to 180
A + B+ C = 180
61+ B + 12 =180
B = 180 - 12 -61
B =107
Then we can use the law of sines to find BC
sin B sin A
-------- = -------------
AC BC
sin 107 sin 61
-------- = -------------
23 BC
Using cross products
BC sin 107 = 23 sin 61
BC = 23 sin 61/ sin 107
BC =21.03540021
Answer:
(3 ± √23 * i) /4
Step-by-step explanation:
To solve this, we can apply the Quadratic Equation.
In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)
Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4
Plugging these values into our equation, we get
x = (-b ± √(b²-4ac))/(2a)
x = (-(-3) ± √(3²-4(2)(4)))/(2(2))
= (3 ± √(9-32))/4
= (3 ± √(-23))/4
= (3 ± √23 * i) /4
1$ = 100 cents, 1 hour = 60 minutes
$7.80/hour = (7.8*100) cents / (1*60)minutes
= 780 cents/60 minutes
= 13 cents/minute
<span>Option b.</span>
