From the order you gave me in the question the answer is equation number
4 1 3 2 6 5
Those are the equation numbers in ascending order based on their radius lengths
Answer:
y = 17(2)^x
Step-by-step explanation:
If the graph of y = ab^x goes through (0, 17), then
17 = ab*0, or a = 17
Then the function is y = ab^x with a = 17, or
y = 17*b^x and we must find b.
If the graph of y = 17*b^x also goes through (6, 1088), then the following must be true: 1088 = 17*b^6
which reduces to 64 = b^6
Taking the sixth root of both sides, we get 64^(1/6) = b, and so b = 2
Then the desired exponential function is
y = 17(2)^x
-4 1/2, -2 3/8, 1.35, 5.6
The ad was around 15 lines.
25.10/5.02 = 5
and then 5 * 3 = 15 lines
