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3 years ago

Translate fifteen more than two times a number into numbers

Mathematics

1 answer:

Crank3 years ago

6 0

Answer:

2x + 15

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=5%20%3C%203%20%2B%20w" id="TexFormula1" title="5 < 3 + w" alt="5 < 3 + w" align="absmidd

Natalija [7]

5-3 < w
2 < w
Hence, w is bigger than 2

3 0

4 years ago

Ava and Sara both started getting an allowance 12 weeks ago, and they haven't spent a cent! They get $1 for each year of their a

4vir4ik [10]

Answer:

Ava is 10 years old

Step-by-step explanation:

Sara is 8

Sara=$8 per week for 12 weeks

$8×12 weeks=$96

Ava has $24 more than Sara

x*12=96$+$24

12x=120

x=120/12

x=10

Ava's age is 10

6 0

3 years ago

A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0

3 years ago

Please help me with homework

Ksivusya [100]

Answer:

1.) 5/4

2.) -4/5

3.) 1/4

4.) -1

5.) 1

Step-by-step explanation:

<u>Brainliest Please</u>

7 0

3 years ago

What number can be add to <br><img src="https://tex.z-dn.net/?f=%20%7B9x%7D%5E%7B2%7D%20%20%2B%2024x" id="TexFormula1" title=" {

4vir4ik [10]

The required number will be 16

the expression will be like :

$9 {x}^{2} + 24x + 16$

$(3x) {}^{2} + (2 \times 3x \times 4) + (4) {}^{2}$

$(3x + 4) {}^{2}$

hope it helps you cap !!

Anti - Venom

5 0

3 years ago