The equation of the tangent to the curve at the point P(2, -10) is:
y = 8x - 26



We need to find the coordinates of point Q where the slope of the tangent to the curve f(x) must also be 8.

Now we have a quadratic:

which simplifies to:

which factorizes to:(x + 4)(x - 2) = 0
Therefore x = -4, 2.
f(-4) = 48
Therefore the coordinates of Q are (-4, 48).
The answer is 0.49 because u jus add it all and minus it from 1
Answer:
Step-by-step explanation:
So on the number line do this...
<--|-----|----|-----|-----|----|----|------|----|----|---->
1/2 1 1-1/2 2 2-1/2 3 3-1/2 4
Label each fraction on the number line.
____________________________________________________________-
The largest amount of snow that fell was 3 and one half (3-1/2)
______________________________________________________________-
The least amount of snow fall was 1 and 1/4(1-2/4)
______________________________________________________________
it snowed 3 days on 3 and 1/4
_____________________________________________________________
Hope this helps you!
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
- Slope Formula:

Step-by-step explanation:
<u>Step 1: Define</u>
Point (-3, -10)
Point (-11, -17)
<u>Step 2: Find slope </u><em><u>m</u></em>
- Substitute:

- Add:

- Simplify:

And we have our final answer!