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Arturiano [62]
3 years ago
11

Sensors send out ............ signals​

Computers and Technology
1 answer:
son4ous [18]3 years ago
3 0

Answer:

mhmm................... ok

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It is considered good practice to save a presentation before printing it. true false
Ilya [14]
It is true because it is really a good practise to save a presentation before printing it

5 0
2 years ago
Coupon collector is a classic statistic problem with many practical applications. The problem is to pick objects from a set of o
ahrayia [7]

Answer:

Here is the JAVA program:

public class Main {  //class name

public static void main(String[] args) {   //start of main method

//sets all boolean type variables spades, hearts diamonds and clubs to false initially

   boolean spades = false;  

   boolean hearts = false;

   boolean diamonds = false;

   boolean clubs = false;  

   String[] deck = new String[4];  //to store card sequence

   int index = 0;  //to store index position

   int NoOfPicks = 0;  //to store number of picks (picks count)

   while (!spades || !hearts || !diamonds || !clubs) {   //loop starts

       String card = printCard(getRandomCard());  //calls printCard method by passing getRandomCard method as argument to it to get the card

       NoOfPicks++;   //adds 1 to pick count

       if (card.contains("Spades") && !spades) {  //if that random card is a card of Spades and spades is not false

           deck[index++] = card;  //add that card to the index position of deck

           spades = true;  //sets spades to true

       } else if (card.contains("Hearts") && !hearts) {  //if that random card is a card of Hearts and hearts is not false

           deck[index++] = card;  

           hearts = true;   //sets hearts to true

       } else if (card.contains("Diamond") && !diamonds) {  //if that random card is a card of Diamond and diamonds is not false

           deck[index++] = card;

           diamonds = true;  //sets diamonds to true

       } else if (card.contains("Clubs") && !clubs) {  if that random card is a card of Clubs and clubs is not false

           deck[index++] = card;

           clubs = true;         }     }   //sets clubs to true

   for (int i = 0; i < deck.length; i++) {  //iterates through the deck i.e. card sequence array

       System.out.println(deck[i]);     }  //prints the card number in deck

   System.out.println("Number of picks: " + NoOfPicks);  }   //prints number of picks

public static int getRandomCard() {  //gets random card

   return (int) (Math.random() * 52); }   //generates random numbers of 52 range

public static String printCard(int cardNo) {   //displays rank number and suit

   String[] suits = { "Spades", "Hearts", "Diamonds", "Clubs", };  //array of suits

   String[] rankCards = { "Ace", "2", "3", "4", "5", "6", "7", "8", "9", "10",

           "Jack", "Queen", "King" };   //array of rank

  int suitNo = cardNo / 13;  //divides card number by 13 and stores to suitNo

 int rankNo = cardNo % 13;   //takes modulo of card number and 13 and store it to rankNo

   return rankCards[rankNo] + " of " + suits[suitNo];  }}  //returns rankCard at rankNo index and suits at suitNo index

Explanation:

The program is explained in the comments attached with each line of code. The screenshot of the program along with its output is attached.

8 0
3 years ago
Assignment
Lena [83]

Answer:

it

is

not

a

big

question

it

is

so

simple

5 0
3 years ago
This unit is used to print the picture on a paper
NeTakaya

Answer:a printer

Explanation:

It prints things

7 0
2 years ago
Q10: Putting it all together (0.75 points) Here, we'll update the values in dictionary, storing the output in a dictionary calle
Molodets [167]

Answer:

# Code in Python

dictionary={'A':1,'B':2,'C':3,'D':4}

other_dictionary={}

for keys in dictionary:

if dictionary[keys]&1==1:

temp=dictionary[keys]*dictionary[keys]-10*10

other_dictionary[keys]=temp

else:

other_dictionary[keys]=dictionary[keys]

print(other_dictionary)  

assert other_dictionary

Explanation:

  • Initialize a sample example dictionary  and other_dictionary.
  • Do a binary comparision for checking odd number .
  • Update the the value stored in the dictionary to store the squared difference of the original value and '10'.
  • For even: store the original value (from dictionary).
4 0
3 years ago
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