The problem domain layer addresses how the software will execute on specific computers and networks.
A problem domain is a software engineering term that refers to all information that defines a problem and compels the solution.
A problem domain basically looks at only the area you are interested in and excludes the rest. It includes the goals the problem owner wishes to have and the context in which the problem exists. For example, if you are creating a website for selling artwork online, the problem domain will be artwork and eCommerce.
Therefore, in order to identify a problem domain, you need to know the relevant user requirements. This can be easy when you start by finding out what people (users) think the problem is.
#SPJ4
The question given is incomplete and by finding it on internet i found the complete question as follows:
Direct Mapped Cache.
Memory is byte addressable
Fill in the missing fields based upon the properties of a direct-mapped cache. Click on "Select" to access the list of possible answers Main Memory Size Cache Size Block Size Number of Tag Bits 3 1) 16 KiB 128 KiB 256 B 20 2) 32 GiB 32 KiB 1 KiB 3) 64 MiB 512 KiB 1 KiB Select] 4 KiB 4) 16 GiB 10 Select ] Select ] 5) 10 64 MiB [ Select ] 6) Select] 512 KiB 7
For convenience, the table form of the question is attached in the image below.
Answers of blanks:
1. 3 bits
2. 20 bits
3. 64 MB
4. 16 MB
5. 64 KB
6. 64 MB
Explanation:
Following is the solution for question step-by-step:
<u>Part 1:</u>
No. of Tag bits = No. of bits to represent
Tag bits = Main memory - cache size bits -------- (A)
Given:
Main memory = 128 KB = 
Cache Memory = 16 KB = 
Putting values in A:
Tag bits = 17 - 14 = 3 bits
<u>Part 2:</u>
Tag bits = Main memory - cache size bits -------- (A)
Given:
Main memory = 32 GB = 
Cache Memory = 16 KB = 
Putting values in A:
Tag bits = 35 - 15 = 20 bits
<u>Part 3:</u>
Given:
Tag bits = 7
Cache Memory = 512 KB = 
So from equation A
7 = Main Memory size - 19
Main Memory = 7 + 19
Main memory = 26
OR
Main Memory = 
<u>Part 4:</u>
Given that:
Main Memory Size = 
Tag bits = 10
Cache Memory Bits = 34 - 10 = 24
Cache Memory Size = 
<u>Part 5:</u>
Given that:
Main Memory Size = 64 MB = 
Tag bits = 10
Cache Memory Bits = 26 - 10 = 16
Cache Memory Size = 
<u>Part 6:</u>
Cache Memory = 512 KB = 
Tag Bits = 7
Main Memory Bits = 19 + 7 = 26
Main Memory size = 
i hope it will help you!
Answer:
final thoughts
Explanation:
it is generally what we should do so that people can know what your opinion on it at the end