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andre [41]
3 years ago
15

2. Question :

Mathematics
2 answers:
mario62 [17]3 years ago
5 0
2.) <span>0.0054 = 5.4 x 10^-3

4.) </span><span>38.1 x 10^-3 = 0.0381

6.) </span><span>In the expression, 6.24 x 10^3, 3 is the exponent

8.) </span><span>In the expression 8.92 x 10^3, 10 is the base</span>
alisha [4.7K]3 years ago
3 0
2. 5.4x10^-3
4. 0.0381
6. 3
8. 10

Hope this helps :)
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How do you write 0.045 as a reduced fraction
Anvisha [2.4K]
0.045 = 45/1000

Divide top and bottom by their greatest common factor.
It looks to me as though the greatest common factor of  45  and  1,000  is  5 .
Divide top and bottom by  5  and we have  <u>9/200</u> .  That's the simplest form.
6 0
3 years ago
Read 2 more answers
Find the LCM and HCF of 110 and 220 by prime factorization what do you observe....pls answer this ​
ElenaW [278]

Answer: Check if numbers are prime. Composite numbers prime factorization (decomposing, breaking numbers down to prime factors). Inscribe them as a product of prime factors, in exponential notation.

8 0
3 years ago
Select the correct answer.
Black_prince [1.1K]
It’s b I think hope this helps you
4 0
3 years ago
$10,000 at an annual rate of 7%, compounded semi-annually, for 2 years
forsale [732]

Answer:

\$13,107.96

Step-by-step explanation:

Since interest is compounded semi-annually (half a year or 6 months), in a spawn of 2 years, the interest will have been compounded 4 times. As given in the problem, each time the interest is compounded, the new balance will be 107% or 1.07 times the amount of the old balance.

Therefore, we can set up the following equation to find the new balance after 2 years:

\text{New balanace}=10,000\text{ (old balance)}\cdot 1.07\cdot 1.07\cdot 1.07\cdot 1.07,\\\text{New balanace}=10,000\cdot 1.07^4=\boxed{\$13,107.96}

8 0
3 years ago
I dont understand this but maybe some one will and they will help me. The quotient of a number and -7 decreased by 2 is ten find
givi [52]
It might be nineteen because nineteen minus seven is twelve. twelve minus two is ten.
8 0
3 years ago
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