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3 years ago

What are the chart and graph numbers?

Mathematics

2 answers:

Anarel [89]3 years ago

6 0

Answ

x and y coordinates

Step-by-step explanation:

motikmotik3 years ago

6 0

Days: bacteria:
1 5
2 10
3 15
4 20
coordinates:
(1,5)
(2,10)
(3,15)
(4,20)

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A straight path from the edge of a circular garden to the center of the garden is 7 meters long. What is the area of the garden?

Dafna11 [192]

Answer:

around 153.94

Step-by-step explanation:

The formula is pi * radius squared

so pi * 7^2 is

pi * 49 = around 153.94

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3 years ago

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If a person walks 16 miles in 10 minutes, how far will that person walk in one hour?

USPshnik [31]

Answer:

too far to be human

Step-by-step explanation:

in 10 mins i walk 1 mile

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Factor the polynomial 9x-6

Afina-wow [57]

Answer:

3(3x-2)

Step-by-step explanation:

this is factoring 3 out of 9x-6

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3 years ago

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Write the standard form of the equation of the circle with endpoints of a diameter at the points (7,2) and (-9,5).

lys-0071 [83]

Answer:

$(x+1)^2 + (y- 3.5)^2 =64$

Step-by-step explanation:

We are given that endpoints of a diameter at the points (7,2) and (-9,5).

Center of the circle is the mid point of diameter

So, first find the mid point of diameter

Formula : $x=\frac{x_1+x_2}{2} , y=\frac{y_1+y_2}{2}$

$(x_1,y_1)=(7,2)\\(y_1,y_2)=(-9,5)$

Substitute the values in formula

$x=\frac{7-9}{2} , y=\frac{2+5}{2}$

$x=-1 , y=3.5$

So, center of circle = (h,k )=(-1,3.5)

To find length of diameter :

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$(x_1,y_1)=(7,2)\\(y_1,y_2)=(-9,5)$

$d=\sqrt{(-9-7)^2+(5-2)^2}$

$d=\sqrt{265}$

Length of radius = r = $\frac{Diameter}{2}=\frac{\sqrt{256}}{2}$

Standard form of the equation of the circle : $(x -h)^2 + (y- k)^2 = r^2$

(h,k )=(-1,3.5)

$r=\frac{\sqrt{256}}{2}$

Equation of the circle : $(x+1)^2 + (y- 3.5)^2 =(\frac{\sqrt{256}}{2})^2$

Equation of the circle : $(x+1)^2 + (y- 3.5)^2 =64$

Hence the standard form of the equation of the circle with endpoints of a diameter at the points (7,2) and (-9,5) is $(x+1)^2 + (y- 3.5)^2 =64$

5 0

3 years ago

What is the factored form of 11x-x^2=0

Aleks [24]

Answer: $x(11-x)=0$

Step-by-step explanation:

Given the quadratic equation $11x-x^2=0$ , you need to factor it.

In order to find the form asked of the given equation, you need to factor out the common factor of the terms.

You can observe that the common factor of the terms of the equation is: $x$

Now, knowing this, you must factor out $x$ . Then you get the following form:

$x(11-x)=0$

Therefore, the factored fom of the equation $11x-x^2=0$ is:

$x(11-x)=0$

3 0

3 years ago