Let the amount invested with 5% interest be x
Therefore, the amount invested with 6% interest will be (6000-x)
It is given that the total interest earned yearly is $337.5. Thus, the equation of interest will be:
Multiplying both sides by 100 we get:
Subtracting both sides by 36000 we get:
Thus, the amount invested at 5% is $2250
Therefore, the amount invested at 6% will be $(6000-2250)=$3750
Answer and Step-by-step explanation:
For 2 dice, we have 36 possibles outcomes:
D₁ = {1,2,3,4,5,6}
D₂ = {1,2,3,4,5,6}
U = ({1,1};{1,2};{1,3};...;{2,1};{2,2};...;{6,6})
This way, it's 6 for D₁ and 6 for D₂, 6.6 = 36
The possible 3 that might appear when rolling a pair of dice would be
{1,2} and {2,1}, so, 2.
The probability of rolling 3 is 2/36 = 1/18
9 ;) thanks that I can help next time I will do better
Answer:
Rounded:
596.05
OR
596.046
Raw:
596.046447754
Step-by-step explanation:
Solved with sci calculator
