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RideAnS [48]
3 years ago
14

Carly wants to fly to Canada, rent a car, and drive 568 miles to visit her sister in a truck that gets 21 miles per gallon. If g

as costs $1.02 per liter, how much will the road trip cost her? There are 3.79 liters in 1 gallon. Round your answer to the nearest cent.
Mathematics
1 answer:
iren2701 [21]3 years ago
3 0

Answer:

$104.56

Step-by-step explanation:

The computation of the cost of the road trip as follows:

The total number of gallons required is

= 568 ÷ 21 miles

= 27.05 gallons.

Now

the cost of one gallon is

= 3.79 × 1.02

= $3.8658

So, the cost of the road trip is

= 27.05 × 3.8658

= $104.56

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25% of what number equals 7?
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28 because 1/4th of 28 is equal to 7
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Angie is canning applesauce for the winter. She has a can that is 6 inches high and 4 inches in diameter. How much applesauce ca
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Step-by-step explanation:

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3 years ago
The television show CSI: Shoboygan has been successful for many years. That show recently had a share of 18, meaning that among
jeyben [28]

Answer:

(a) The value of P (None) is 0.062.

(b) The value of P(at least one) is 0.938.

(c) The value of P(at most one) is 0.253.

(d) The event is not unusual.

Step-by-step explanation:

Let <em>X</em> = number of households watching the show.

The probability of the random variable <em>x</em> is, P (X) = <em>p</em> = 0.18.

The sample selected for the survey is of size, <em>n</em> = 14

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 14 and <em>p</em> = 0.18.

The probability of a Binomial distribution is computed using the formula:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,...

(a)

Compute the probability that none of the households are tuned to CSI: Shoboygan as follows:

P(X=0)={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}=1\times1\times0.06214=0.062

Thus, the value of P (None) is 0.062.

(b)

Compute the probability that at least one household is tuned to CSI: Shoboygan as follows:

P (X ≥ 1) = 1 - P (X < 1)

             = 1 - P (X = 0)

             =1-0.062\\=0.938

Thus, the value of P(at least one) is 0.938.

(c)

Compute the probability that at most one household is tuned to CSI: Shoboygan as follows:

P (X ≤ 1) = P (X = 0) + P (X = 1)

             ={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}+{14\choose 1}(0.18)^{1}(1-0.18)^{14-1}\\=0.062+0.191\\=0.253

Thus, the value of P(at most one) is 0.253.

(d)

An event that has a very low probability of occurrence is known as an unusual event.

The probability of the event "at most one household is tuned to CSI: Shoboygan" is 0.253.

This probability value is not low.

Hence, the event is not unusual.

5 0
3 years ago
Simplify the expression. (3.5x - 5) + (7.2x + 10)
Andru [333]

Answer: 10.7x + 5

Step-by-step explanation:

(3.5 + 7.2)x + (-5 + 10) = 10.7x + 5

8 0
3 years ago
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