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pshichka [43]
4 years ago
7

A selection of staff wages is collected and shown below. £254 £254 £310 £276 £116 £90 £312 £180 £180 £536 £350 £243 £221 £165 £2

39 £700 What is the mean of the staff wages?
Mathematics
2 answers:
Tresset [83]4 years ago
5 0

Answer:

276.625

Step-by-step explanation:

Add all the totals up and divide by how many groups there are

Add up all the wages and divide by the number of wages so 16 sets of wages which equals 276.625

AleksAgata [21]4 years ago
3 0
Mean of the staff wage is the average of the staff wage=total wage/total number of staff
( 254+254+310+276+116+90+312+180+537+350+243+221+165+239+700)/16=276+5/8
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Step-by-step explanation:

5/45 = 1/9

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A ratio that is equivalent to 5/45 is 1/9!

Hope This Helps :)

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Answer:

Step-by-step explanation:

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3 years ago
HELP <br><br>Determine whether the relation is a function<br><br> y=2w=2​
nexus9112 [7]

Answer:

Hi there!

I might be able to help you!

It is NOT a function.

<u>Determining whether a relation is a function on a graph is relatively easy by using the vertical line test. If a vertical line crosses the relation on the graph only once in all locations, the relation is a function. However, if a vertical line crosses the relation more than once, the relation is not a function</u>. <u>X = y2 would be a sideways parabola and therefore not a function.</u> Good test for function: Vertical Line test. If a vertical line passes through two points on the graph of a relation, it is <em>not </em>a function. A relation which is not a function. The x-intercept of a function is calculated by substituting the value of f(x) as zero. Similarly, the y-intercept of a function is calculated by substituting the value of x as zero. The slope of a linear function is calculated by rearranging the equation to its general form, f(x) = mx + c; where m is the slope.

A relation that is not a function

As we can see duplication in X-values with different y-values, then this relation is not a function.

A relation that is a function

As every value of X is different and is associated with only one value of y, this relation is a function.

Step-by-step explanation:

It's up there!

God bless you!

3 0
3 years ago
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