Answer:
In HTML file
<body style="background-color:orange;">
Or
In CSS file
body {
background-color: orange;
}
Explanation:
Simplify the Boolean expression (AB(C + BD) + AB]CD.
Answer:
Option B i.e., a lack of bonding is the correct answer.
Explanation:
Cohesion is defined as the ability to work in a group, so many time the following situation or problems that are lack of bonding occurs between the mates or the group members because while they achieving their goals there is the understanding problem may occur between them or sometime their ideas should be a mismatch.
import random
def random_number_file_writer(nums):
f = open("random.txt", "w")
i = 0
while i < nums:
f.write(str(random.randint(1,500))+"\n")
i += 1
f.close()
def random_number_file_reader():
f = open("random.txt", "r")
total = 0
count = 0
for x in f.readlines():
total += int(x)
count += 1
print("The total of the numbers is "+str(total))
print("The number of random numbers read from the file is "+str(count))
def main():
random_number_file_writer(int(input("How many random numbers do you want to generate? ")))
random_number_file_reader()
main()
I hope this helps!
Explanation:
Let, DG is the datagram so, DG= 2400.
Let, FV is the Value of Fragment and F is the Flag and FO is the Fragmentation Offset.
Let, M is the MTU so, M=700.
Let, IP is the IP header so, IP= 20.
Let, id is the identification number so, id=422
Required numbers of the fragment = ![[\frac{DG-IP}{M-IP} ]](https://tex.z-dn.net/?f=%5B%5Cfrac%7BDG-IP%7D%7BM-IP%7D%20%5D)
Insert values in the formula = ![[\frac{2400-20}{700-20} ]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B2400-20%7D%7B700-20%7D%20%5D)
Then, =
= ![[3.5]](https://tex.z-dn.net/?f=%5B3.5%5D)
The generated numbers of the fragment is 4
- If FV = 1 then, bytes in data field of DG=
and id=422 and FO=0 and F=1.
- If FV = 2 then, bytes in data field of DG=
and id=422 and FO=85
and F=1.
- If FV = 3 then, bytes in data field of DG=
and id=422 and FO=170
and F=1.
- If FV = 4 then, bytes in data field of DG=
and id=422 and FO=255
and F=0.