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3 years ago

Please help it urgent!!!!

Mathematics

1 answer:

Veronika [31]3 years ago

4 0

Answer:

first box: 5 * 7 = 35

35 x^2

second box: 5 * -1 = -5

-5x

third box: 5 * 8 = 40

answer: 35 $x^{2}$ - 5x + 40

first box: 2x * 4x^2

2 * 4 = 8

x * x^2 = x^3

8x^3

second box: 2x * 3x

2 * 3 = 6

x * x = x^2

6x^2

third box: 2x * 6

2 * 6 = 12

12x

answer: 8x^3 + 6x^2 + 12x

top left box: tp * 4p

p * p = p^2

4t $p^{2}$

top right box: tp * - 6

-6tp

bottom left box: 5 * 4p

5 * 4 = 20

20p

bottom right box: 5 * - 6

5 * -6 = -11

-11

answer: 4tp^2 - 6tp + 20p - 11

top left box: 4a * 8a

4 * 8 = 32

a * a = a^2

32a^2

top right box: 4a * -1

4 * -1 = -4

-4a

bottom left box: -8 * 8a

-8 * 8 = -64

-64a

bottom right box: -8 * - 1

-8 * - 1 = 8

32a^2 - 4a - 64a + 8

<em>combine like terms</em>

32a^2 - 68a + 8 = answer

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Of the last 24 balloons sold at a party store 6 were white. Find the experimental probability that the next balloon sold will be

Alekssandra [29.7K]

Answer: 1 out of 4

Step-by-step explanation:

If you divided the total amount of balloons that were sold by the amount of white balloons, it would be 4. The 1 comes from 1 in 4 being the probability of them being white. You can check this by multiplying the 1 and 4 by 6 and it would be 6 out of 24, which shows our answer is correct.

8 0

4 years ago

A buyer went to the market to buy strawberries. He purchased 120 randomly selected strawberries from a vendor who claimed that n

mafiozo [28]

Answer:

$z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10$

$p_v =P(z>2.10)=0.018$

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

Step-by-step explanation:

Data given and notation

n=120 represent the random sample taken

X=40 represent the number of strawberries damaged

$\hat p=\frac{40}{120}=0.333$ estimated proportion of strawberries damaged

$p_o=0.25$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that no more than 25% of his total harvest of strawberries was damaged.:

Null hypothesis: $p\leq 0.25$

Alternative hypothesis: $p > 0.25$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.10)=0.018$

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

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3 years ago

T5 ( volume of cylinder )

yan [13]

Answer:

Step-by-step explanation:

$V=\pi r^2h=\pi *20^2*8$ ≈ $10053.1in^3$