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Thepotemich [5.8K]
2 years ago
14

For each direct variation find the constant of variation then find the value of Y when X equals -0.5. Y equals 2 when X equals 3

Mathematics
1 answer:
Readme [11.4K]2 years ago
4 0

For direct variation y varies directly with x, then we use equation y = kx

Where k is the constant of proportionality

Given: Y equals 2 when X equals 3

We plug in 3 for x  and 2 for y and solve for k

y = kx

2 = k(3)

Divide both sides by 3

\frac{2}{3} =k

Now we plug in 2/3 for k  

y=\frac{2}{3}x

Given x=-0.5  and find out y

y=\frac{2}{3}(-0.5)

y=-0.33

the value of y is -0.33 when x=-0.5


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Step-by-step explanation:

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0= x²−4x+y²+10y+13 = (x-2)²+ 4  + (y+5)²-25+13 = (x-2)²+(y+5)² - 8

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Thus

f(x) = \sqrt{-x^2+4x+4} - 5

g(x) = -\sqrt{-x^2+4x+4} - 5

Lets find the derivate of each function and the points in which they reach the value 2/3. In those points the tangent line will have a slope of 2/3.

We may just find the values of x which the derivate of f is either 2/3 or -2/3.

\frac{-x+2}{\sqrt{-x^2+4x+4}} = ^+_-\frac{2}{3} \Leftrightarrow \frac{x^2-4x+4}{-x^2+4x+4} = \frac{4}{9} \Leftrightarrow 9(x^2-4x+4) = 4(-x^2+4x+4) \\\Leftrightarrow 13x^2-52x+20 = 0

The quadratic has roots

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one root is 3.568, which corresponds with g, and the other root is 0.431, corresponding to f.

Also g(3.568) = - 7.354 and f(0.431) = -2.646

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