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Serjik [45]
3 years ago
14

Finding Circumference

Mathematics
2 answers:
Ratling [72]3 years ago
5 0

Answer:

3

Step-by-step explanation:

16 \times 2 \times 3.14 = 100.48

Slav-nsk [51]3 years ago
5 0

Answer:

100.48

Step-by-step explanation:

the formula for circumference is C = 2 (pi) r

2(3.14)(16)=100.48

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Alexxx [7]

if you have a zero exponent, the number (or the base) equals 1

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4 years ago
Write the grammatical sentence as an algebraic one: Nine less than half a number is twenty-four. ​
soldi70 [24.7K]
Answer:

x/2-9=24

Explanation:

Nine less:
-9
Half a number:
x/2
So nine less than half a number:
x/2-9
Is 24:
=24

So x/2-9=24

To solve for the number:
Add 9 to both sides:
x/2-9+9=24+9
x/2=33
Multiply both sides by 2:
2(x/2)=33(2)
x=66
8 0
3 years ago
The park service that administers a state park estimates that there are 495 deer in the park. They decide to remove deer accordi
Vlada [557]

Answer:

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Step-by-step explanation:

6 0
3 years ago
What is the answer 1 2 3 or 6
katrin2010 [14]
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7 0
3 years ago
Read 2 more answers
I need help in partial fraction!! With simple explaination would be nice!
WITCHER [35]
\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}

The degree of the numerator (4) is larger than the degree of the denominator (3), so first you need to divide. (Added screenshot of long division procedure.)

\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x-\dfrac{4x^2-17x+10}{x(x^2-3)}

Now the second term can be decomposed into partial fractions.

\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1}x+\dfrac{r_2x+r_3}{x^2-3}
\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1(x^2-3)+x(r_2x+r_3)}{x(x^2-3)}
4x^2-17x+10=r_1(x^2-3)+x(r_2x+r_3)
4x^2-17x+10=(r_1+r_2)x^2+r_3x-3r_1
\implies\begin{cases}r_1+r_2=4\\r_3=-17\\-3r_1=10\end{cases}\implies r_1=-\dfrac{10}3,r_2=\dfrac{22}3,r_3=-17=-\dfrac{51}3
\implies\dfrac{4x^2-17x+10}{x(x^2-3)}=-\dfrac{10}{3x}+\dfrac{22x-51}{x^2-3}

So

\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x+\dfrac{10}{3x}-\dfrac{22x-51}{x^2-3}

3 0
3 years ago
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