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Angelina_Jolie [31]
3 years ago
13

The park service that administers a state park estimates that there are 495 deer in the park. They decide to remove deer accordi

ng to the differential equation dP/dt = −0.1P.
a. Show that the solution to the differential equation dP/dt = −0.1P is P = 495e^−0.1t , where t is measured in years and P is the population of deer. Use it to find the deer population in 5 years to the nearest deer.

b. After this 5-year period, no human intervention is taken and the deer population grows again. From that time, the deer population increases directly proportional to 650−P, where the constant of proportionality is k. Find an equation for the deer population P(t) in terms of t and k for this 5-year period.

c. Using the growth model from part b), 1 year later the deer population is 350. Find k.

d. Using the growth model from part b) and the value of k from part c), find lim t→∞ P(t)
Mathematics
1 answer:
Vlada [557]3 years ago
6 0

Answer:

your answer is (A.)

Step-by-step explanation:

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Ludmilka [50]
                               x^2 = 16/100
We must solve for x by taking the square root of both sides.
But imagine x^2 = 9. x = 3 is a solution because 3^2 = 9. But x = -3 is also a solution because (-3)^2 = 9. So we need to add the plus and minus sign to account for all of our solutions.
                     √x^2 = √(16/100)
We square root both sides to remove the exponent 2 on x. Then
                         x = ±√(16/100)
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