Answer:
0.79
Step-by-step explanation:
Here,
Let X be the event that the flights depart on time
Let Y be the event that flights arrive on time
So,
X∩Y will denote the event that the flights departing on time also arrive on time.
Let P be the probability
P(X∩Y)=0.65
And
P(X)=0.82
We have to find P((Y│X)
We know that
P((Y│X)=P(X∩Y)/P(X) )
=0.65/0.82
=0.79
So the probability that a flight that departs on schedule also arrives on schedule is: 0.79
Answer: AB
Step-by-step explanation:
AB is on the sideways of AD=BC.
Answer:
$420
Step-by-step explanation:
Calculate 3% of 3,500:
0.03*3500 = 105
105 per year for 4 years:
105*4 = 420
Answer:
The range of the function is:
Range R = {14, 17, 20}
Step-by-step explanation:
Given the function

We also know that range is the set of values of the dependent variable for which a function is defined.
In other words,
- Range refers to all the possible sets of output values on the y-axis.
We are given that the domain of the function is:
Domain D = {4, 5, 6}
Now,
substituting x = 4 in the function
f(4) = 3(4) + 2
f(4) = 12 + 2
f(4) = 14
substituting x = 5 in the function
f(5) = 3(5) + 2
f(5) = 15 + 2
f(5) = 17
substituting x = 6 in the function
f(6) = 3(6) + 2
f(6) = 18 + 2
f(6) = 20
Thus, we conclude that:
at x = 4, y = 14
at x = 5, y = 17
at x = 6, y = 20
Thus, the range of the function is:
Range R = {14, 17, 20}
Answer:
191
Step-by-step explanation:
17.70---- 177
19.10-----191
First just take 177/17.70= 10
all you have to do is multiply by 10
so
19.10= 191