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Gemiola [76]
2 years ago
6

A surveyor is calculating the width of a canyon. He has taken the measurements shown below. What is the width of the canyon? Typ

e a numerical answer in the box below.

Mathematics
1 answer:
Serga [27]2 years ago
8 0

Answer:

480 ft

Step-by-step explanation:

To find the width (x), apply the similarity theorem of two similar triangles, which says that the corresponding lengths of two similar triangles are proportional.

Thus:

x/72 = 80/12

Cross multiply

12 × x = 80 × 72

12x = 5,760

12x/12 = 5,760/12

x = 480

Width of the canyon = x = 480 ft

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HEEEEEELP PLLLEEEEEEEZZZZZZ!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
stellarik [79]

C is correct,

A is wrong as it halves both the angles and lengths by two which is the same as what she did in the first place so it cannot be correct.

B is also wrong for a similar reason, a triangle cannot have less than 180 degrees, which is impossible as the angles just change naturally which is why all triangles must have 180 degrees, which is the reason she is wrong in the first place.

And D is just incorrect, if she wanted to have shorter sides she should have only decreased all the lengths as it the the ratio of angles that determine the shape of a triangle while the sum of all angles is 180 degrees.

7 0
2 years ago
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1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch
kykrilka [37]
Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle. 

Thus, half the angle formed by the chord at the centre of the circle is given by:

\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2}  \\  \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o

Now, 

\sin60^o= \frac{9}{r}  \\  \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392

Therefore, the radius of the circle is 10.4 cm to 1 d.p.


Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o

Now, 

\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm


Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

\sin40^o= \frac{y}{10}  \\  \\  \\ \Rightarrow y=10\sin40^o=6.428

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.
3 0
3 years ago
Lenny worked 7 hours on Wednesday, 6 hours on Thursday, and 9 hours on Friday. His gross pay for all three days was $196.90.
Elza [17]

Answer:

8.95

Step-by-step explanation: Add the hours and divide the money by the amount of hours

7 0
2 years ago
Find the Area of the Circle.
Sergio [31]
200.96
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2 years ago
Find the slope of the line that passes through the pair of points.
Korolek [52]

Answer:

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Step-by-step explanation:

Slope = (y2-y1)/ (x2-x1)

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= -1.4/41.72

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3 0
2 years ago
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