Answer:
there are only 4 whole numbers whose squares and cubes have the same number of digits.
Explanations:
let 0, 1, 2 and 4∈W (where W is a whole number), then
,
,
,
,
,
,
,
.
You can see from the above that only four whole numbers are there whose squares and cubes have the same number of digits
Use math away it’s a really good source
Answer:

Step-by-step explanation:
The general equation of a circle is as follows:

In which the center is
, and r is the radius.
In this problem, we have that:

So

Passing through (2,-4)
We replace into the equation to find the radius.



The equation of the circle is:

You can do this by drawing one line through parallel to PQS to meet RQ at T
Now calculate length of RT:-
cos 70 = RT / 70 giving RT = 23.94m
sin 70 = ST/70 giving ST = 65.78 m
draw a line from S perpendicular to PQ to meet PQ at U.
PU = 110 - 65.78 = 44.22 m
tan 50 = SU / 44.22 giving SU = 52.70 m
TQ = SU = 52.70 m
So x = TQ + RT = 52.70 + 23.94 = 76.6 m to 1 dec place.