Answer:
y=5x+100
Step-by-step explanation:
x represents every square foot
The polar coordinate system.
Step-by-step explanation:






Taking sin²θ common in both numerator & denominator, We get :










<u>Hence</u><u>,</u><u> option</u><u> </u><u>(</u><u>a)</u><u> </u><u>2</u><u>/</u><u>3</u><u> </u><u>is </u><u>your</u><u> </u><u>correct</u><u> </u><u>answer</u><u>.</u>
Answer:
$542
Step-by-step explanation:
we know that
The equation of a exponential decay function is given by

where
y is the value of the lawnmower
x is the time in years
a is the initial value
r is the rate of change
we have

substitute


For x=5 years
