So listen to this logic
lets say you have 3 numbers, m,a,x where they are all positivie
m>a>x
therefor
m^2>a>2>x^2
if m and a and x are square roots, therefor we can reverse the square root
confusing sorry
square 5 and 6
5^2=25
6^2=36
the number betwe 25 and 36
that would be 32
answer is √32
goes like this
5^2<32<6^2
sqrt both sides
5<√32<6
answer is √32
Idk...................................
X = -1!
1. Factor out 2 from the expression : 2(x-5) / 4 = 3x
2. Reduce the fraction with 2 : x-5 / 2 = 3x
3. Multiply both sides of the equation by 2 : x-5=6x
4. Move the terms : x - 6x = 5
5. Collect like terms : -5x = 5
6. Divid both sides by -5
Hope this helps!
