This is the last one I promise!!

A construction crew is lengthening a road that originally measured 47 miles. The crew is adding one mile to the road each day. L

Dmitry_Shevchenko [17]

Answer:

78 miles

Step-by-step explanation:

Given that:

Original length, L = 47 miles

Additional length (miles) added per day, = 1 mile

Representing as an equation :

L(D) = original length + additional length per day * number of days

Let, D = number of days

L(D) = 47 + D

Length after 31 days :

L(31) = 47 + 31

= 78 miles

3 0

3 years ago

Write an expression to represent the total cost of paint at a rate of $5.75 per ft.? to paint a triangular-shaped mural where th

ASHA 777 [7]

Answer:

C($)= (x²/2 +11x)5.75

Step-by-step explanation:

Let's assume the height= x

The base= x+22

Area= 1/2(base*height).

Area= 1/2((x+22)(x))

Area= x²/2 +11x

Cost per ft= $5.75

Cost for painting the triangular mural C

C($)= (x²/2 +11x)5.75

7 0

2 years ago

the area for any square is given by the function y=x squared where is the length of a side of the area square and y is the area

Angelina_Jolie [31]

12.25 inches. the equation to find that would be 3.5 squared or 3.5 times 3.5

5 0

3 years ago

What time is 5 3/4 hours after 9:22 pm?

Ronch [10]

Answer:

15:37 or 3:37

Step-by-step explanation:

3/4=0.75

0.75+9.22=9.97

5+9.97=14.97

6 0

2 years ago

Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe

nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that one person in 10,000 people has a rare genetic disease.

So, $P(D)=\frac{1}{10000}$

Only 0.4% of the people who don't have it test positive.

$P(A|D^c)$ = probability that a person is tested positive given he don't have a disease = 0.004

$P(D^c)=1-\frac{1}{10000}$

Formula: $P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}$

$P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}$

P(D|A)= $\frac{2470}{2471}$ =0.9995

P(D|A)= $0.9995$

A)The probability that someone who tests positive has the disease is 0.9995

(B)

$P(D^c|A^c)$ =probability that someone does not have disease given that he tests negative

$P(A^c|D^c)$ =probability that a person tests negative given that he does not have disease =1-0.004

=0.996

$P(A^c|D)$ =probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: $P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}$

$P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}$

$P(D^c|A^c)=0.99999$

B)The probability that someone who tests negative does not have the disease is 0.99999

8 0

3 years ago