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Finger [1]
2 years ago
14

What is the range for 46 47 52 55 64 69 70 78

Mathematics
1 answer:
GalinKa [24]2 years ago
4 0

Answer:

range you can calculate maximum value - minimum value 78- 46=32

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Let $f(x) = 2x^2 + 3x - 9,$ $g(x) = 5x + 11,$ and $h(x) = -3x^2 + 1.$ Find $f(x) - g(x) + h(x).$
Viefleur [7K]

QUESTION 1

Given that:

f(x)=2x^2+3x-9,

g(x)=5x+11,

and

h(x)=-3x^2+1

Then;

f(x)-g(x)+h(x)=2x^2+3x-9-(5x+11)+(-3x^2+1)

f(x)-g(x)+h(x)=2x^2+3x-9-5x-11-3x^2+1

Group similar terms;

f(x)-g(x)+h(x)=2x^2-3x^2+3x-5x-11-9+1

Simplify;

f(x)-g(x)+h(x)=-x^2-2x-19

QUESTION 2

Given that;

f(x)=4x-7.

g(x)=(x+1)^2

and

s(x)=f(x)+g(x)

Substitute the functions;

s(x)=4x-7+(x+1)^2

Substitute x=3

s(3)=4(3)-7+(3+1)^2

s(3)=12-7+(4)^2

s(3)=5+16

s(3)=21

QUESTION 3

Given:

f(x)=3x+2

g(x)=x^2-5x-1

f(g(x))=f(x^2-5x-1)

This implies that;

f(g(x))=3(x^2-5x-1)+2

Expand the parenthesis;

f(g(x))=3x^2-15x-3+2

f(g(x))=3x^2-15x-1

QUESTION 4

The given function is;

f(x)=3(x-6)^2+1

Let

y=3(x-6)^2+1

\Rightarrow y-1=3(x-6)^2

\Rightarrow \frac{y-1}{3}=(x-6)^2

\Rightarrow \sqrt{\frac{y-1}{3}}=x-6

\Rightarrow x=6+\sqrt{\frac{y-1}{3}}

The range is:

\frac{y-1}{3}\ge0

y-1\ge0

y\ge1

The interval notation is;

[1,+\infty)

6 0
3 years ago
Solve.<br><br> y = –4x + 10<br> y = –3x + 5
saw5 [17]
The answers in order are
Y= 10/4
Y=5/3
8 0
2 years ago
Read 2 more answers
The radius of circle L is 16 cm. 
timurjin [86]
The anwser is for the question tht u are looking for is no other then the first anwser A!!!
6 0
3 years ago
What are the x-intercept(s) and y-intercept(s) of the graph above.
dem82 [27]

Answer:

A

Step-by-step explanation:

X-intercepts are points on the graph where a line crosses the x-axis (horizontal line).

Given in the graph, the line goes through x-axis at the values -1 on the left, 1, and 2.

Y-intercepts are points on the graph where a line crosses the y-axis (vertical line).

Looking at the graph, the line only goes through the y-axis on the value 2.

Therefore, A is the only logical answer.

3 0
2 years ago
What is the lateral area of the prism?<br><br> cm2
laiz [17]
LA = (2l + 2w)h

Plug in what we know:

LA = (2(11) + 2(7))(4)

Multiply:

LA = (22 + 14)(4)

Add:

LA = 36(4)

Multiply:

LA = 144
3 0
3 years ago
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