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3 years ago

I need some answers please like I really don’t know how to do these problems at all

Mathematics

2 answers:

PSYCHO15rus [73]3 years ago

8 0

Answer:

EVALUATE THE FUCTION WHEN: f (1/2 % 32)////////21+×_37- 4 = 37.2

EVALUATE THE FUNCTION WHEN f(3+38 x + formula of angle are = _1/2 decimals point 78.32)*/% =3( 92.03

Step-by-step explanation:

HOPE IT HELPS A LOT!!

ollegr [7]3 years ago

3 0

That answer that he put in is wrong. Hold on I’ll give you the right answer

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Answer: Domain: {2}

Step-by-step explanation:

1. By definition, the domain is the input value, this means that it is the x-value of a function.

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4 years ago

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When the sample size and the sample proportion remain the same, a 90 percent confidence interval for a population proportion p w

deff fn [24]

Answer:

A 90% confidence interval for p will be narrower than the 99% confidence interval.

Step-by-step explanation:

The formula to compute the (1 - α) % confidence interval for a population proportion is:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Here $\hat p$ is the sample proportion.

The margin of error of the confidence interval is:

$MOE= z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The MOE is dependent on:

Confidence level
Standard deviation
Sample size

The MOE is directly related to the confidence level and standard deviation.

So if any of the two increases then the MOE also increases, thus widening the confidence interval.

And the MOE is inversely related to the sample size.

So if the sample increases the MOE decreases and vice versa.

It is provided that the sample size and the sample proportion are not altered.

The critical value of z for 90% confidence level is:

$z_{\alpha/2}= z_{0.10/2}=z_{0.05}=1.645$

And the critical value of z for 99% confidence level is:

$z_{\alpha/2}= z_{0.05/2}=z_{0.05}=1.96$

So as the confidence level increases the critical value increases.

Thus, a 90% confidence interval for p will be narrower than the 99% confidence interval.

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3 years ago