Original position:
A-(-8,-4)
B-(-6,3)
C-(-3,7)
D-(-2,-2)
Translation:
A'-(-4,-4)
B'-(-2,3)
C'-(1,7)
D'-(2,-2)
Vertex C will be in quadrant 1 (+,+) after being translated 4 unites to the right.
The identity in question is
cos(a - b) = cos(a) cos(b) + sin(a) sin(b)
so that
cos(a - b) = 12/37 cos(a) + 3/5 sin(b)
Since both a and b lie in the first quadrant, both cos(a) and sin(b) will be positive. Then it follows from the Pythagorean identity,
cos²(x) + sin²(x) = 1,
that
cos(a) = √(1 - sin²(a)) = 4/5
and
sin(b) = √(1 - cos²(b)) = 35/37
So,
cos(a - b) = 12/37 • 4/5 + 3/5 • 35/37 = 153/185
Answer:
y=x
Step-by-step explanation:
domain: all real numbers
range: all real numbers
X/Y Intercept: (0,0)
7x+3y=-1
x+y=-3
8x+4y=-4
2x+y=-1
y=-1-2x
x+y=-3
x-1-2x=-3
-x=-2
x=2
y=-1-2*2=-1-4=-5
1634/19=86. Hope this helps
