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Fiesta28 [93]
3 years ago
11

In a program you need to store identification numbers of 5 employees and their weekly gross pay.

Computers and Technology
1 answer:
Allushta [10]3 years ago
4 0

Solution :

a). The two arrays that are used in parallel in order to store the identification of two numbers of 5 employees and their weekly gross payments is  :

  int id_array[5];

  double gross_pay[5];

b). The loop that uses the arrays for printing the identification number and the weekly gross payment  is given below :

 for(int i=0; i<5; i++)

  {

  count <<id_array[i] <<" " << gross_pay[i] << end;

  }

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3 years ago
Write an application that determines whether the first two files are located in the same folder as the third one. The program sh
marissa [1.9K]

Answer:

The program in Python is as follows:

fname1 = input("Filepath 1: ").lower()

fname2 = input("Filepath 2: ").lower()

fname3 = input("Filepath 3: ").lower()

f1dir = ""; f2dir = ""; f3dir = ""

fnamesplit = fname1.split("/")

for i in range(len(fnamesplit)-1):

   f1dir+=fnamesplit[i]+"/"

fnamesplit = fname2.split("/")

for i in range(len(fnamesplit)-1):

   f2dir+=fnamesplit[i]+"/"

fnamesplit = fname3.split("/")

for i in range(len(fnamesplit)-1):

   f3dir+=fnamesplit[i]+"/"

if f1dir == f2dir == f3dir:

   print("Files are in the same folder")

else:

   print("Files are in the different folder")

Explanation:

The next three lines get the file path of the three files

<em>fname1 = input("Filepath 1: ").lower()</em>

<em>fname2 = input("Filepath 2: ").lower()</em>

<em>fname3 = input("Filepath 3: ").lower()</em>

This initializes the directory of the three files to an empty string

f1dir = ""; f2dir = ""; f3dir = ""

This splits file name 1 by "/"

fnamesplit = fname1.split("/")

This iteration gets the directory of file 1 (leaving out the file name)

<em>for i in range(len(fnamesplit)-1):</em>

<em>    f1dir+=fnamesplit[i]+"/"</em>

This splits file name 2 by "/"

fnamesplit = fname2.split("/")

This iteration gets the directory of file 2 (leaving out the file name)

<em>for i in range(len(fnamesplit)-1):</em>

<em>    f2dir+=fnamesplit[i]+"/"</em>

This splits file name 3 by "/"

fnamesplit = fname3.split("/")

This iteration gets the directory of file 3 (leaving out the file name)

<em>for i in range(len(fnamesplit)-1):</em>

<em>    f3dir+=fnamesplit[i]+"/"</em>

This checks if the file directories hold the same value

This is executed, if yes

<em>if f1dir == f2dir == f3dir:</em>

<em>    print("Files are in the same folder")</em>

This is executed, if otherwise

<em>else:</em>

<em>    print("Files are in the different folder")</em>

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Answer:

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So that the company's addressing can be executed successfully, the use of NATs is enabled, this allows the translation of network addresses, allowing the company to have as many private networks as necessary and that these can be communicated Correctly with the global network, the Internet, through the public IP of the company.

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