#7:
<span>Subtract </span>y<span> from both sides:
</span>-4x=6-y
Divide both sides by -4:
Answer:
x= -6-y/4
#7 part 2:
Add <span>y</span><span> to both sides:
</span>-5x=21+y
Divide both sides by -5:
Answer: x=-21+y/5
hope i helped!
<span><span><span>s+12</span>+<span>3s</span></span>−8</span><span>=
<span><span><span><span>s+12</span>+<span>3s</span></span>+</span>−8
</span></span>Combine Like Terms<span>
<span><span><span>s+12</span>+<span>3s</span></span>+<span>−8</span></span></span><span>=
<span><span>(<span>s+<span>3s</span></span>)</span>+<span>(<span>12+<span>−8</span></span>)</span></span></span><span>=
<span><span>4s</span>+<span>4</span></span></span>
To make the inequality, we will use the ≥ sign to determine how many more tickets we will need. Before we write the inequality, let's see how much money was already made by the present tickets. 70 x 9.50 = $665.
We can write the inequality as $665 + $9.50t ≥ $1000 where t is the number of tickets sold. Now we can solve
$665 + $9.50t ≥ $1000, subtract 665
$9.50t ≥ $335. Now isolate the t by divide 9.50 to both sides
t ≥ 35.26 which we can round up to 36 because you cant sell 35.26 tickets.
So you need at least 36 more tickets to earn at least $1000
Um do you have a picture that we can look at because we can't help you if we don't have a picture of the problem.
There are C(30, 6) = 30!/(6!*(30-6)!) = 593,775 ways to pick 6 numbers from the first 30 positive integers.
The probabilty of matching 6 randomly chosen integers is 1/593,775.
