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2 years ago

Doing a Pre-Algebra Unit Test on Khan Academy

Mathematics

2 answers:

larisa [96]2 years ago

8 0

Answer:

-8,8

Step-by-step explanation:

since y=8 that add 8 to both sides to get rid of the -y. you would then get -4x=32. divide 32 by -4 and you would get -8 so the missing value would be -8

natta225 [31]2 years ago

5 0

Answer:

x=-8

Step-by-step explanation:

First, lets change the standerd form to slop intercept

$-y=24+4x$

$y=-24-4x$

Now, let's subsite for y, and solve for x

$8=-24-4x$

$32=-4x$

$-8=x$

CHECK:

32-8=24

$24=24$

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Jaun has 105 feet of rope he needs to cut into sections 7/8 feet long . how many sections can be cut

AVprozaik [17]

The answer is 120 sections.

Here's an explanation:

The rope is 105 feet long, and each section needs to be 7/8 feet. So to find the number of sections, you need to divide 105 by 7/8. 105 divided by 7/8 gives you the quotient 120. So there are 120 sections.

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3 years ago

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vlada-n [284]

Answer:

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Step-by-step explanation:

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3 years ago

A photo processing place can develop 416 photos in 8 hours. How many photos can it develop every hour?

Rina8888 [55]

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3 years ago

What is the measure of angle B in the triangle?

Marat540 [252]

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8 0

3 years ago

Read 2 more answers

Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options. The radius of the cir

FromTheMoon [43]

The statements which are correct about the equation of circle $x^{2} +y^{2}-2x-8=0$ are 1) The radius of the circle is 3 units,2) The center of the circle lies on the x axis,5) The radius of this circle is the same the radius of the circle whose equation is $x^{2} +y^{2} =9$ .

Given the equation of circle be $x^{2} +y^{2}-2x-8=0$ .

We are required to find the appropriate statements related to the equation $x^{2} +y^{2}-2x-8=0$ .

$x^{2} +y^{2}-2x-8=0$ can be written as under:

$x^{2} +y^{2} -2x+1-9=0$

$x^{2} +1^{2}-2x+y^{2} -9=0$

$(x-1)^{2}+y^{2}$ -9=0

$(x-1)^{2} +y^{2} =9$

$(x-1)^{2}+y^{2} =3^{2}$

Equation of a circle usually in the form $x^{2} +y^{2} =a^{2}$ in which a is radius.

From the comparison of both the equations we get that radius is 3 units.

From the equation point will be (1,0). It is on the x axis.

Hence the statements which are correct about the equation of circle $x^{2} +y^{2}-2x-8=0$ are 1) The radius of the circle is 3 units,2) The center of the circle lies on the x axis,5) The radius of this circle is the same the radius of the circle whose equation is $x^{2} +y^{2} =9$ .

Learn more about radius at brainly.com/question/24375372

#SPJ1

3 0

1 year ago