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gayaneshka [121]
2 years ago
8

Doing a Pre-Algebra Unit Test on Khan Academy

Mathematics
2 answers:
larisa [96]2 years ago
8 0

Answer:

-8,8

Step-by-step explanation:

since y=8 that add 8 to both sides to get rid of the -y.  you would then get -4x=32.  divide 32 by -4 and you would get -8 so the missing value would be -8

natta225 [31]2 years ago
5 0

Answer:

x=-8

Step-by-step explanation:

First, lets change the standerd form to slop intercept

-y=24+4x

y=-24-4x

Now, let's subsite for y, and solve for x

8=-24-4x

32=-4x

-8=x

CHECK:

32-8=24

24=24

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If sin(theta) =4/5 and is in quadrant 2, the value of cot(theta
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\sin\theta= \frac{4}{5} 
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\\\sin^2\theta+\cos^2\theta=1
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\theta \in II \Rightarrow \cos\theta\ \textless \ 0 \Rightarrow \cos\theta=-\frac{3}{5}

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What is the solution of the equation 4p/6+27
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Consider the equation 3x + 1 = 2x + 5
fomenos
You can’t technically solve it because there’s no question
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A researcher believes that the mean weight of competitive runners is about 140 pounds. A sample of 24 elite distance runners has
ExtremeBDS [4]

Answer:

t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781    

p_v =P(t_{(23)}  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=136 represent the sample mean

s=11 represent the sample standard deviation

n=24 sample size  

\mu_o =140 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less than 140, the system of hypothesis would be:  

Null hypothesis:\mu \geq 140  

Alternative hypothesis:\mu < 140  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=24-1=23  

Since is a one left tailed test the p value would be:  

p_v =P(t_{(23)}  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.  

4 0
3 years ago
PLS HELP!! WILL GIVE YOU BRAINLEST
prisoha [69]

Answer:

y=0x+3

y=3x-11

2,11

Step-by-step explanation:

This is the answer I know. let me know if I'm wrong

6 0
3 years ago
Read 2 more answers
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