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kap26 [50]
3 years ago
10

Footballs sell for $27.99 each at the Sports R' Us and for $21.59 each at the Fitness Depot. If the coach buys a dozen footballs

, how much can he save by buying them at the Fitness Depot?
Mathematics
1 answer:
nata0808 [166]3 years ago
4 0

Answer:

He can save $76.8 by buying them at the Fitness Depot.

Step-by-step explanation:

If the coach buys a dozen footballs, it means that he buys 12 and first, you need to determine the cost of purchasing the 12 footballs at each store by multiplying the amount of footballs for the price at each store.

-Sports R' Us: $27.99*12=$335.88

-Fitness Depot: $21.59*12=$259.08

Then, you have to find the difference between the total cost at both places:

$335.88-$259.08=$76.8

According to this, the answer is that he can save $76.8 by buying them at the Fitness Depot.

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Korolek [52]
46 yards is the answer

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Victoria buys two pair of sunglasses for $8 each. About how much did she pay for both pairs of glasses? Round to the nearest ten
kumpel [21]

Victoria buys 2 pairs of sunglasses for $8 each

1 pair of glasses = $8

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hope this helps

7 0
3 years ago
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Ratio of sandwiches white bread to brown bread is 10:3. 2/3 white are vegetarian, half brown are vegetarian. What fraction of th
julsineya [31]
<h3>Answer:</h3>

8/13

<h3>Step-by-step explanation:</h3>

Given in the question

Ratio of sandwiches white bread to brown bread is 10 : 3

white bread fraction = 10/13

brown bread fraction = 3/13

It is also provided that

2/3 white are vegetarian

1/2 brown are vegetarian

So

for white bread vegetables sandwich we will find 2/3 of 10

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for brown bread vegetable sandwich we will find 1/2 of 3

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adding both

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3 0
3 years ago
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stealth61 [152]
0.1, guessing they mean largest in value
4 0
3 years ago
A set of mathematics exam scores are normally distributed with a mean of 80.280.280, point, 2 points and a standard deviation of
hichkok12 [17]

Answer:

0.3745

Step-by-step explanation:

Data

mean (\mu): 80

standard deviation (\sigma): 4

Normal distribution table is in figure attached .

Z = \frac{x - \mu}{\sigma&#10;}

Z = (85 - 80)/4 = 1.25

Area below curve = 0.3944

Z = (82 - 80)/4 = 0.5

Area below curve = 0.0199

Proportion of exam scores between 82 and 85?

0.3944 - 0.0199 = 0.3745

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3 years ago
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