The expected value of this policy to the insurance company is $285.00.
Using this formula
Policy expected value=Insurance policy charges-[(Probability × Claim)+(Probability × Claim)]
Let plug in the formula
Policy expected value=$1,300-{(.0041)($150,000)+(.08)($5,000)]
Policy expected value=$1,300-($615+$$400)
Policy expected value=$1,300-$1,015
Policy expected value=$285.00
Inconclusion the expected value of this policy to the insurance company is $285.00
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<span> log3x − 5 16 = 2
+516 +516
log3x=518
x=(10^518)/3
the answer seems a bit crazy, you probably typed something wrong</span>
Answer:
3/4
Step-by-step explanation:
A: students present
B: students on time
P(all students present and on time) = P(A and B) = 3/10
P(all students present) = P(A) = 2/5
P(A and B) = P(A).P(B|A) where P(B|A) is the probability of everyone being on time given that everyone is present
So P(B|A) = P(A and B) /P(A) = 3/10 ÷ 2/5 = 3/10 * 5/2 = 15/20 which can be reduced to 3/4 by dividing numerator and denominator by 5
Answer: First one is B second one just make it
Step-by-step explanation:
Factors of 24.
1, 2, 3, 4, 6, 8, 12, and 24<span>. </span>