3 years ago

Three consecutive integers have a sum of 81 . Find the integers.

Mathematics

1 answer:

Yuri [45]3 years ago

3 0

The 3 consecutive integers of a sum of 81X+(X+2)+(X+4)=81
3X+6=81
3X=81-6
3X=75
X=75/3

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user100 [1]

Answer:

The simplified expression is:

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Step-by-step explanation:

Given the expression

$\frac{2}{5}y+\frac{1}{5}x-0.2y-6+\left(-2\right)$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{2}{5}y+\frac{1}{5}x-0.2y-6-2$

$\mathrm{Group\:like\:terms}$

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Add similar elements

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Step-by-step explanation:

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