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3 years ago

I have 3/4 of all my kittens and 3/4 of a kitten. How many kittens do I have?

Mathematics

1 answer:

Ostrovityanka [42]3 years ago

7 0

Answer:

i think 6/8

Step-by-step explanation:

3/4 x 3/4

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Pratap Puri rowed 14 miles down a river in 2 hours, but the return trip took him 3 and one half hours. Find the rate Pratap can

SOVA2 [1]

speed of current is 1.5 mi/hr

Answer:

let the rate in still water be x and rate of the current be y.

speed down the river is:

speed=distance/time

speed=14/2=7 mi/h

speed up the river is:

speed=(14)/(3.5)=4 mi/hr

thus total speed downstream and upstream will be:

x+y=7...i

x-y=4.......ii

adding the above equations i and ii we get:

2x=11

x=5.5 mi/hr

thus

y=5-5.5=1.5 mi/r

thus the speed in still waters is 5.5 mi/hr

speed of current is 1.5 mi/hr

7 0

2 years ago

An arithmetic sequence is defined by its 1st term a1 = 7 and the sum of the first 10 terms s10 = 25. Find the difference d of th

VARVARA [1.3K]

Step-by-step explanation:

difference is 1.8

hope it is correct

3 0

2 years ago

What is 9/10 of a yard

igor_vitrenko [27]

(9/10)x3 feet
= (9/10)x36 inches
= 32.4 inches

4 0

3 years ago

Erik and Caleb were trying to solve the equation: 0=(3x+2)(x-4) Erik said, "The right-hand side is factored, so I'll use the zer

Mumz [18]

Answer:

C) Both

Step-by-step explanation:

The given equation is:

$0=(3x+2)(x-4)$

To solve the given equation, we can use the Zero Product Property according to which if the product <em>A.B = 0</em>, then either A = 0 OR B = 0.

Using this property:

$(3x+2) = 0 \Rightarrow \bold{x = -\frac{2}{3}}\\(x-4) = 0 \Rightarrow \bold{x = 4}$

So, Erik's solution strategy would work.

Now, let us discuss about Caleb's solution strategy:

Multiply $(3x+2)(x-4)$ i.e. $3x^2-12x+2x-8$ = $3x^2-10x-8$

So, the equation becomes:

$0=3x^2-10x-8$

Comparing this equation to standard quadratic equation:

$ax^2+bx+c=0$

a = 3, b = -10, c = -8

So, this can be solved using the quadratic formula.

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-(-10)\pm\sqrt{(-10)^2-4\times3 \times (-8)}}{2\times 3}\\x=\dfrac{-(-10)\pm\sqrt{196}}{6}\\x=\dfrac{10\pm14}{6} \\\Rightarrow x= 4, -\dfrac{2}{3}$

The answer is same from both the approaches.

So, the correct answer is:

C) Both

3 0

3 years ago

Show that 5(3y-2)=15y-10 for at least 5 values of y

Vsevolod [243]

<span>Solving the equation for Y = 1. 5 * (3 * 1 - 2) = 15 * 1 - 10 5 * (3 - 2) = 15 -10 5 * 1 = 5 5 = 5 Solving the equation for Y = 2. 5 * (3 * 2 - 2) = 15 * 2 - 10 5 * (6 - 2) = 30 -10 5 * 4 = 20 20 = 20 Solving the equation for Y = 4. 5 * (3 * 4 - 2) = 15 * 4 - 10 5 * (12 - 2) = 60 -10 5 * 10 = 50 50 = 50 Solving the equation for Y = 8. 5 * (3 * 8 - 2) = 15 * 8 - 10 5 * (24 - 2) = 120 -10 5 * 22 = 110 110 = 110 Solving the equation for Y = 9. 5 * (3 * 9 - 2) = 15 * 9 - 10 5 * (27 - 2) = 135 -10 5 * 25 = 125 125 = 125 This proves that the equation holds good for at least 5 values of 'y', which are 1, 2, 4, 8 and 9. However, it can be proved that the equation holds good for any value of y. Expression 5(3y-2) can be simplified to 15y -10 which is the same expression on the right had side of the equation provided. So, equation 5(3y-2)=15y-10 is actually 15y-10=15y-10 and since this is true for all values of y, it has been proved that it is true for at least 5 values of y.</span>

7 0

3 years ago