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Nitella [24]
1 year ago
9

Please help me i need to finish this i’m tired (please use grid if you can) asap!!!

Mathematics
1 answer:
jasenka [17]1 year ago
8 0

The linear equation is y = 4x - 4

And the graph of the linear equation can be seen in the image below.

<h3>How to graph the last line?</h3>

It seems that you already are good at graphing, so I will try to explain how to find the equation more in detail.

Remember that a general linear equation is written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

In this case, we know that the y-intercept is -4, then b = -4, replacing that we get:

y = a*x - 4

Now we also can see that this line passes through the point (2, 4), this means that if we evaluate in x = 2, the outcome should be y = 4, replacing that we get:

4 = a*2  - 4

4 + 4 = a*2

8 = a*2

8/2 = a = 4

Then the slope is 4, and the linear equation is:

y = 4x - 4

The graph is below.

If you want to learn more about linear functions:

brainly.com/question/4025726

#SPJ1

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Step-by-step explanation:

Let the number be y & reciprocal simply means inverse of the number

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4/y=2/8; y = 16

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Answer:

a) We need to conduct a hypothesis in order to test the claim that the true proportion p is greatr than 0.3, so then the system of hypothesis are.:  

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Right tailed test

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Step-by-step explanation:

Part a: Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion p is greatr than 0.3, so then the system of hypothesis are.:  

Null hypothesis:p \leq 0.3  

Alternative hypothesis:p > 0.3  

Right tailed test

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

For this case the statistic is given by z_{calc}= 2.32

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The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.32)=0.0102  

Part c

So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is higher than 0.3

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