Speed=frequency*wavelength
Given
frequency=1200\ Hz
and
wavelength=0.300\ m
we get:
speed=1200\ Hz*0.300\ m=360\ m/s
Explanation:
It is given that,
Height, h = 3.1 m
Initial speed of the rocket, u = 0
Final speed of the rocket, v = 28 m/s
(b) Let a is the acceleration of the rocket. Using the formula as :
(a) Let t is the time taken to reach by the rocket to reach to a height of h. So,
t = 0.22 seconds
(c) At t = 0.1 seconds, height of the rocket is given by :
h = 0.63 meters
(d) Let v' is the speed of the rocket 0.10 s after launch.
So,
v' = 12.64 m/s
Hence, this is the required solution.
Answer:
The rate at which work is done is called <em>Powe</em><em>r</em><em>.</em>
<em>hop</em><em>e</em><em> it</em><em> helps</em><em>!</em>