Question

One of the dangers of tornados and hurricanes is the rapid drop in air pressurethat is associated with such storms. Assume that the air pressure inside of a sealed houseis 1.02 atm when a hurricane hits. The hurricane rapidly decreases the external airpressure to 0.910 atm. What net outward force is exerted on a square window of thehouse that is 2.03 m on each side

Answer 1

Answer:

The net outward force is exerted on a square window of the house is $4.5930\times10^{4}\ N$.

Explanation:

Given that,

Pressure = 1.02 atm

External air pressure = 0.910 atm

Distance = 2.03 m

We need to calculate the net outward force

Using formula of force

$F= PA$

Where, P = pressure

F = force

A = area

Put the value into the formula

$F=(1.02-0.910)\times101325\times(2.03)^2$

$F=4.5930\times10^{4}\ N$

Hence, The net outward force is exerted on a square window of the house is $4.5930\times10^{4}\ N$.