Calculate the length of AC, to the nearest tenth of a centimeter.
1 answer:
Answer:
AC ≈ 11.0 cm
Step-by-step explanation:
Using Pythagoras' identity in Δ CDE and Δ ADE
CE² + DE² = DC²
CE² + 7² = 8²
CE² + 49 = 64 ( subtract 49 from both sides )
CE² = 15 ( take the square root of both sides )
CE =
-------------------------------------------------------
AE² + DE² = DA²
AE² + 7² = 10²
AE² + 49 = 100 ( subtract 49 from both sides )
AE² = 51 ( take the square root of both sides )
AE =
Then
AC = AE + CE = +
≈ 11.0 cm ( to the nearest tenth )
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Answer:
Procedure in option C only works.
Step-by-step explanation:
We have to select the process in which Mrs. Smith can help her to work 30 divided by 3.
(A) (27 divided by 9) + (9 divided by 3) = 3 + 3 = 6
But (30 ÷ 3) = 10 ≠ 6
(B) (24 divided by 4) + (4 divided by 4) = 6 + 1 = 7 ≠ 10
(C) (21 divided by 3) + (9 divided by 3) = 7 + 3 = 10
(D) (20 divided by 4) + (10 divided by 4) = 5 + 2.5 = 7.5 ≠ 10
So, procedure in option C only works. (Answer)
Again, we can prove the procedure in the following way:
{Which is the distributive property of division}