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ryzh [129]
2 years ago
13

Calculate the length of AC, to the nearest tenth of a centimeter.

Mathematics
1 answer:
sertanlavr [38]2 years ago
5 0

Answer:

AC ≈ 11.0 cm

Step-by-step explanation:

Using Pythagoras' identity in Δ CDE and Δ ADE

CE² + DE² = DC²

CE² + 7² = 8²

CE² + 49 = 64 ( subtract 49 from both sides )

CE² = 15 ( take the square root of both sides )

CE = \sqrt{15}

-------------------------------------------------------

AE² + DE² = DA²

AE² + 7² = 10²

AE² + 49 = 100 ( subtract 49 from both sides )

AE² = 51 ( take the square root of both sides )

AE = \sqrt{51}

Then

AC = AE + CE = \sqrt{15} + \sqrt{51} ≈ 11.0 cm ( to the nearest tenth )

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Mashutka [201]

Answer:

B. y = 2x

Step-by-step explanation:

every y value is the value of x multiplied by 2

so that means y=2x

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5 0
2 years ago
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How do I solve this?
Sonbull [250]

The question is somewhat poorly posed because the equation doesn't involve <em>θ</em> at all. I assume the author meant to use <em>x</em>.

sec(<em>x</em>) = csc(<em>x</em>)

By definition of secant and cosecant,

1/cos(<em>x</em>) = 1/sin(<em>x</em>)

Multiply both sides by sin(<em>x</em>) :

sin(<em>x</em>)/cos(<em>x</em>) = sin(<em>x</em>)/sin(<em>x</em>)

As long as sin(<em>x</em>) ≠ 0, this reduces to

sin(<em>x</em>)/cos(<em>x</em>) = 1

By definition of tangent,

tan(<em>x</em>) = 1

Solve for <em>x</em> :

<em>x</em> = arctan(1) + <em>nπ</em>

<em>x</em> = <em>π</em>/4 + <em>nπ</em>

(where <em>n</em> is any integer)

In the interval 0 ≤ <em>x</em> ≤ 2<em>π</em>, you get 2 solutions when <em>n</em> = 0 and <em>n</em> = 1 of

<em>x</em> = <em>π</em>/4   <u>or</u>   <em>x</em> = 5<em>π</em>/4

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2 years ago
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Artemon [7]
The answer is Yes, no, yes, no
7 0
2 years ago
What is the solution of the system? Use the elimination method. 2x+y=206x−5y=12 Enter your answer in the boxes.
astraxan [27]

Answer:

The answer to your question is:   x = 7; y = 6

Step-by-step explanation:

                                             2x+y=20             ( 1 )  Multiply by 5

                                             6x−5y=12            ( 2 )

                               5 (2x+y=20)    = 10x + 5y = 100

                                          10x + 5y = 100

                                            6x − 5y =   12             Eliminate y

                                          16 x        = 112

                                           x = 112 / 16

                                           x = 7

                                 2(7) + y = 20                 Substitution

                                 14 + y = 20

                                 y = 20 - 14

                                 y = 6

7 0
3 years ago
Geometry Help
sergiy2304 [10]
I hope this helps you

7 0
3 years ago
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