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EastWind [94]
2 years ago
15

How can we create equations in two variables to represent relationships between quantities

Mathematics
1 answer:
goldfiish [28.3K]2 years ago
7 0

Answer:

Create equations in two or more variables to represent relationships between quantities (linear functions) Create equations in two or more variables to represent relationships between quantities; graph equations on coordinate axes with labels and scales.

Step-by-step explanation:

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Which of the numbers below belong to the solution set for x-7>3
beks73 [17]
It cant be 7 because,
X-7>3
7-7>3
0>3
And 0 is not bigger than 3

It cant be 9 because,
X-7>3
9-7>3
2>3
And 2 is not bigger than 3

So it is 11 because,
X-7>3
11-7>3
4>3
And 4 is bigger than 3

So the answer is 3) 11
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3 years ago
1/3 x 8 in simplest form
makvit [3.9K]

In mathematics, every integer is a rational number, hence a whole number 8 can be written as 8/1. 1/3 x 8 = 8/3 in fraction form. 1/3 x 8 = 2.6667 in decimal form.

7 0
2 years ago
Help asap please!!!!!!​
Andrews [41]

Step-by-step explanation:

[(-3 × 2 × (-4)] ÷ [-6 × 12]

[3 × 2 × -4] ÷ [-6 × 12]

[6 × -4]/[-6 × 12]

-4/(-1 × 12]

-4/-12

⅓

Option A is wrong

Option B is wrong -9/-18 = ½ not ⅓

Option C is correct = -24/-72 = ⅓

Option D is wrong = 9/-18 = -½ not ⅓

3 0
2 years ago
Find the vertex and length of the latus rectum for the parabola. y=-1/2(x-2)^2+8
victus00 [196]
Y = -(1/2)(x-2)² +8
Re write it in standard form:
(y-8) = -1/2(x-2)²  ↔ (y-k) = a(x-h)²

This parabola open downward (a = -1/2 <0), with a maximum shown in vertex
The vertex is (h , k) → Vertex(2 , 8)
focus(h, k +c )
 a = 1/4c → -1/2 = 1/4c → c = -1/2, hence focus(2, 8-1/2) →focus(2,15/2)

Latus rectum: y-value = 15/2

Replace in the equation y with 15/2→→15/2 = -1/2(x-2)² + 8
Or -1/2(x-2)² +8 -15/2 = 0
Solving this quadratic equation gives x' = 3 and x" = 2, then 
Latus rectum = 5

4 0
3 years ago
What is the linear equation representing the value of the robot? [t is measured in years, V is measured in thousands.]
makvit [3.9K]
All of the above or C
8 0
3 years ago
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