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3 years ago

What energy transformations take place from the outlet charger to the ringing phone?

Physics

1 answer:

il63 [147K]3 years ago

7 0

Answer:

Chemical energy transformations take place from the outlet charger to the ringing phone.

Explanation:

chemical energy

While charging the mobile electrical energy gets transformed into chemical energy. Most of the contemporary mobile phone batteries are lithium-ion batteries where the power is saved by the chemical transformations in the ionic structure of the battery. When the power gets into the mobile phone it is transformed and collected as chemical energy inside of the battery and when we utilize the mobile the earlier saved chemical energy is again transformed into electrical energy.

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Answer:

gravity

Explanation:

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Diffraction of sound waves is demonstrated when sound waves with a frequency of 1300 Hz from a distant source are diffracted thr

Tresset [83]

Answer:

39.05°

Explanation:

As we know that, the diffraction is the phenomena of bending of light when it passes through an obstacle.

Mathematically,

$dsin\theta=n\lambda$

Here, d is slit width, $\lambda$ is the wavelength, n is the order, $\theta$ is the angle.

Given that, d is 84 cm, n is 2, and the wavelength can be calculated as,

$\lambda=\frac{c}{f}$

Here, c is the speed of sound and f is the frequency of sound wave.

Here, c is 343 m/s and f is 1300 Hz,

Therefore,

$\lambda=\frac{343 m/s}{1300 Hz}\\\lambda=0.264m$

Recall diffraction equation in term of $sin\theta$ .

$sin\theta=\frac{n\lambda}{d}$

Put all the variables.

$sin\theta=\frac{2\times 0.264 m}{84 cm}\\sin\theta=\frac{2\times 0.264 m}{0.84 m}\\\theta=39.05^{\circ}$

Therefore, it is the required angle between the first 2 order of diffraction.

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3 years ago

What happen to tbe brightness when one of the bulb removed from patallel circiut

lawyer [7]

The current decreases as the overall resistance increases. In addition, if one bulb is removed from the “chain” the other bulbs go out. ... If light bulbs are connected in parallel to a voltage source, the brightness of the individual bulbs remains more-or-less constant as more and more bulbs are added to the “ladder”.

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3 years ago

A small car with a mass of 800kg moving with a velocity of 27.8 m/s. The car stops at a yellow light in 3.9 seconds. What force

raketka [301]

Answer:

F = 5702.56 N

Explanation:

Given that,

Mass of a small car, m = 800 kg

Initial speed of the car, u = 27.8 m/s

Final speed, v = 0

Time, t = 3.9 s

We need to find the force did it take for the car to stop.

The force acting on an object is given by :

$F=ma\\\\F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{800\times (0-27.8)}{3.9}\\\\F=-5702.56\ N$

So, the magnitude of force acting on the car to stop is 5702.56 N.

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lutik1710 [3]

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