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If a football is kicked from the ground with a speed of 16.71 m/s at an angle of 49.21 degrees, then the vertical component of the initial velocity would be 12.65 m/s
<h3>What is Velocity?</h3>
The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object. The unit of velocity is meter/second.
As given in the problem A football is kicked from the ground with a speed of 16.71 m/s at an angle of 49.21 degrees
The horizontal component of the velocity is given by
Vx = Vcosθ
The vertical component of the velocity is given by
Vy = Vsinθ
As we have to find the vertical component of the velocity given that speed of 16.71 m/s at an angle of 49.21 degrees from the ground
Vy = 16.71 × sin49.21°
Vy = 12.65 m/s
Thus, the vertical component of the velocity would be 12.65 m/s
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It runs slower <span>as gravity is lower so acceleration due to gravity is smaller</span>
Answer:
Ernest Rutherford observed that particles with a positive charge deflected when passing through a thin sheet of gold foil, concluding that the atom's positive part is small and dense.
Explanation:
The Ernest Rutherford experiment describes planetary model of an atom. According to the model, an atom has a tiny, compact, positively charged centre called a nucleus, where almost all of the mass is concentrated, while light, negatively charged particles called electrons orbit far around it, much like planets orbit the Sun. In his experiment, the observation that a positive charge is deflected through a thin sheet of gold foil led to the conclusion that the deflection some of the positive charge occurs in a small region of the atom. At the same time, the majority passed through the atom (which was also concluded to be empty space).
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