An acrostic poem for transformation simply refers to those simple poems conveying transformation messages in which the first letter of each line forms a word or phrase vertically.
<h3>What is poem?</h3><h3 />
A poem can be defined as a a piece of writing in which the expression of feelings and ideas is given intensity by particular attention to diction.
So therefore, an acrostic poem for transformation simply refers to those simple poems conveying transformation messages in which the first letter of each line forms a word or phrase vertically.
Complete question:
What do you understand by acrostic poem for transformation?
Learn more about poem:
brainly.com/question/9861
#SPJ1
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
The tension is 
b
The time taken is 
c
The position for maximum velocity is
S = 0
d
The maximum velocity is
Explanation:
The free body for this question is shown on the second uploaded image
From the question we are told that
The mass of the bob is 
The angle is 
The length of the string is 
The tension on the string is mathematically represented as

substituting values


The motion of the bob is mathematically represented as

=> 
Where
is the angular speed
and
is the phase change
At initial position S = 0
So 

Generally
can be mathematically represented as

Where T is the period of oscillation which i mathematically represented as

So



substituting values


Looking at the equation

We see that maximum velocity of the bob will be at S = 0
i. e 
The maximum velocity is mathematically represented as

Where A is the amplitude which is mathematically represented as

So

Recall 
substituting values
Answer:
B. Convection
Explanation:
Convection is the process in which heat is transferred from one point to another by the actual movement of the material particles from a region of high temperature to a region of low temperature.