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LuckyWell [14K]
3 years ago
13

Why do astronomers use spectroscopes to analyze light from distant objects?

Physics
1 answer:
RoseWind [281]3 years ago
7 0
Spectroscopy — the use of light from a distant object to work out the object is made of — could be the single-most powerful tool astronomers use, says Professor Fred Watson from the Australian Astronomical Observatory. ... "It lets you see the chemicals being absorbed or emitted by the light source.
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What is the centripetal force that would be required to keep a 4.0 kg mass moving in a horizontal circle with a radius of 0.80 m
KIM [24]

Answer:

D. 1.8 × 102 newtons radially inward

Explanation:

The magnitude of the centripetal force is given by:

F=m\frac{v^2}{r}

where

m is the mass of the object

v is the tangential speed

r is the radius of the circular trajector

In this problem, we have m = 4.0 kg, v = 6.0 m/s and r = 0.80 m, therefore substituting into the equation we get

F=(4.0 kg)\frac{(6.0 m/s)^2}{0.80 m}=180 N

The centripetal force is the force that keeps the object in a circular trajectory, so it is a force that is always directed inward (towards the centre of the circular path) and radially. Therefore, the correct answer is

D. 1.8 × 102 newtons radially inward

4 0
3 years ago
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Water changes from a liquid to a gas in the process of evaporation. Please select the best answer from the choices provided T F
const2013 [10]
The correct answer is T.
6 0
3 years ago
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PLLSSSS HELP<br> MARKING BRAINLIST<br> SCIENCE
Sveta_85 [38]

Answer:

the first one

Explanation: the first one because they were all on two different continents so when they seperated half of the species went on one continent and the other half went onto another one

3 0
2 years ago
The magnitude of the electric field between two parallel charged plates is 200. An electron moves to the negative plate 5. 0 cm
Mama L [17]

The potential difference between the two ends of the circuit is the electric potential difference. The electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.

<h3>What is an electric field?</h3>

An electric field is an electric property that is connected with any location in space where a charge exists in any form. The electric force per unit charge is another term for an electric field.

The given data in the problem is given by;

E is the electric field = (200 N/C)

d is the distance = 5.0 cm.=0.05 m

Q is the charge of electrons= 1.602 x 10^-19 C

The formula for electric potential  is given by;

\rm V=Ed

\rm V=Ed \\\\ \rm V=200 \times 0.05 \\\\ \rm V=  10 \frac{Nm}{C} = 10 \frac{J}{C}  = 10 V.

The work is defined as the product of the potential difference and charge of an electron.

\rm W= 10 \times  1.602 x 10^{-19} \\\\\ \rm W=  1.6 x 10^{-18 }J

Hence the electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.

To learn more about the electric field refer to the link;

brainly.com/question/15071884

8 0
2 years ago
The top speed you will ever need to go in a parking lot is_
Kruka [31]

10 mph i jus got it right on the test

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