Ask question

Ask question

All categories

3 years ago

7

Consider a cube that measures 1 inch on each side. We can think of a cubic foot as a dilation of the cubic inch by a factor of 1

2. What is the volume, in cubic inches, of a cubic foot? *

1 answer:

Irina-Kira [14]3 years ago

3 0

Answer:

ii

Step-by-step explanation:

Add the length, width, height, and then multiply by 2 so you have the cube, then multiply by 12 so you should have an equation of 2(3 X 12)

You might be interested in

Write the smallest possible length. length:9.15 (to 2 decimal places)

pentagon [3]

<span>9.145 is the smallest value that will round to 9.15.

</span><span>As the rule that if that digit is less than 5, do not change the rounding digit but drop all digits to the right of it. So it should be 5 to 9 but then the question above is looking for the smallest possible number which is 5. </span>

3 0

3 years ago

Read 2 more answers

Please help me out ...

fgiga [73]

Angle1 = 90 degrees

Angle2 = 15 degrees

Angle3 = 75 degrees (because 180-15-90=75 and all angles equal 180 degrees)

Side1 = 300

Side2 = x (unknown)

Solve for x:

X / sin(15degrees) = 300 / sin(75degrees)

X = (300•sin(15degrees)) / sin(75degrees)

X = 80.38...

= 80

8 0

4 years ago

In ΔBCD, the measure of ∠D=90°, the measure of ∠B=31°, and CD = 1.6 feet. Find the length of BC to the nearest tenth of a foot.

son4ous [18]

Answer:

3.1066≈3.1 feet

Step-by-step explanation:

3.1066≈3.1 feet

6 0

3 years ago

Read 2 more answers

Which set of numbers could represent the lengths of the sides of a triangle? A. 2, 2, 4 B. 7, 4, 3 C. 6, 12, 5 D. 9, 8, 15

Alja [10]

Answer:

D

i just guest hope its right

4 0

2 years ago

Simplify the expression ((81y^-8)/(16x^20))^-1/4

Darina [25.2K]

$\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------$

$\bf \left( \cfrac{81y^{-8}}{16x^{20}} \right)^{-\frac{1}{4}}\implies \left( \cfrac{16x^{20}}{81y^{-8}} \right)^{\frac{1}{4}}\implies \left( \cfrac{2^4x^{20}}{3^4y^{-8}} \right)^{\frac{1}{4}}
\\\\\\
\textit{and now we'll distribute the exponent}\qquad \left( \cfrac{2^{4\cdot \frac{1}{4}}x^{20\cdot \frac{1}{4}}}{3^{4\cdot \frac{1}{4}}y^{-8\cdot \frac{1}{4}}} \right)
\\\\\\
\cfrac{2^1x^5}{3^1y^{-2}}\implies \cfrac{2^1x^5y^2}{3^1}\implies \cfrac{2x^5y^2}{3}$

6 0

3 years ago